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3 years ago

What is 972 written in standard form?

Mathematics

2 answers:

Romashka [77]3 years ago

6 0

Answer:

9.72 × 10²

Step-by-step explanation:

A number written in standard form is of the form

a × $10^{n}$ ( where 1 ≤ a < 10 and n is an integer )

We require to write the number between 1 and 10 , that is

9.72 × $10^{n}$

To get the number back to its true value we require to multiply by 100, then

972 = 9.72 × 100 = 9.72 × 10² ← in standard form

Annette [7]3 years ago

4 0

Answer:

9*100+7*10+2*1

Step-by-step explanation:

hope you like it

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50 POINTS

Marina86 [1]

vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.

Givens

vi = 160 ft/s

vf = 0 (the rocket stops at the maximum height.)

a = - 9.81 m/s

t = ????

Remark

YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.

Equation

a = (vf - vi)/t

Solve

- 32 = (0 - 160)/t Multiply both sides by t

-32 * t = - 160 Divide by -32

t = - 160/-32

t = 5

You will also need to solve for the height to answer part B

t = 5

vi = 160 m/s

a = - 32

d = ???

d = vi*t + 1/2 a t^2

d = 160*5 + 1/2 * - 32 * 5^2

d = 800 - 400

d = 400 feet

Part B

You are at the maximum height. vi is 0 this time because you are starting to descend.

vi = 0

a = 32 m/s^2

d = 400 feet

t = ??

formula

d = vi*t + 1/2 a t^2

400 = 0 + 1/2 * 32 * t^2

400 = 16 * t^2

400/16 = t^2

t^2 = 25

t = 5 sec

The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.

6 0

3 years ago

The frequency distribution representing the number of frequent flier miles accumulated by employees at Brumley Statistical Consu

alisha [4.7K]

Answer:

a. How many employees accumulated less than 3,000 miles?

The number of employees accumulated less than 3,000 miles= 5

So the number of employees accumulated less than 3,000 miles is 5.

d. Based on the cumulative frequency polygon, about 75% of the employees accumulated how many miles or less?

8.5 thousands of miles, found by starting at 75 percent on the vertical axis on the right, over to the polygon and then down to the horizontal axis.

Step-by-step explanation:

The given frequency distribution representing the number of frequent flier miles accumulated by the employees in a company.

Frequent Flier Miles (000) Frequency

0 up to 3 5

3 up to 6 12

6 up to 9 23

9 up to 12 8

12 up to 15 2

Total 50

a. How many employees accumulated less than 3,000 miles?

The number of employees accumulated less than 3,000 miles= 5

So the number of employees accumulated less than 3,000 miles is 5.

b. Convert the frequency distribution to a cumulative frequency distribution.

We make the cumulative frequency distribution from the frequency distribution by adding up a frequency and all other frequencies below it.

Frequent Flier Miles Frequency Cumulative frequency

0 up to 3 5 5

3 up to 6 12 17

6 up to 9 23 40

9 up to 12 8 48

12 up to 15 2 50

Total 50

d. Based on the cumulative frequency polygon, about 75% of the employees accumulated how many miles or less?

8.5 thousands of miles, found by starting at 75 percent on the vertical axis on the right, over to the polygon and then down to the horizontal axis.

8 0

3 years ago

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

1 year ago

Simplify the product using the distributive property. (-4h +2)(3h +7)

Alekssandra [29.7K]

Answer:

A. -12h² - 22h + 14

Step-by-step explanation:

(-4h +2)(3h +7) = -4h(3h +7) +2(3h +7) . . . . . . . (a +b)c = ac +bc

= (-4h)(3h) + (-4h)(7) + (2)(3h) + (2)(7) . . . . . . . a(b +c) = ab +ac . . . (twice)

= -12h² -28h +6h +14

= -12h² -22h +14 . . . . . . . . collect terms

3 0

3 years ago

If (−7, m) is on a circle with center c(3, 5) and radius 10, what is the value of m? m = 5 m equals negative five plus two squar

AfilCa [17]

${(x - 3)}^{2} + {(y - 5)}^{2} = 100 \\ 100 + {(y - 5)}^{2} = 100 \\ y = 5$

7 0

3 years ago