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puteri [66]
3 years ago
10

What is the value of 1/2x3 + 3.4y when x = 3 and y =4

Mathematics
1 answer:
coldgirl [10]3 years ago
6 0
You need to substitude the value into the formula given

1/2(3)^3 + 3.4(4)
= 1/2(27) + 13.6
= 27/2 + 13.6
= 27.1
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PLEASE HELP!!! I will give brainliest answer!!! Find the volume and surface area of these.
k0ka [10]

Answer:

(I only have the answers for 3 and 4) 3. Volume: 192 Surface Area: 16 4. Volume: 1,200 Surface Area: 100

Step-by-step explanation:

3. Volume: 4 x 4 = 16 x 12 = 192 Surface Area: 4 x 4 = 16 4. Volume: 10 x 10 = 100 x 12 = 1,200 Surface Area: 10 x 10 = 100

4 0
3 years ago
How to write the ratio 8:30 as a fraction in simplest form
omeli [17]
4/15 because you make it into a fraction: 8/30, you find the GCF which is 2, so then you divide both the numerator and denominator by 2 and get 4/15 at it's simplest term
5 0
3 years ago
The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM. If 188 sixth graders
Anna007 [38]

Answer:

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM.

This means that \mu = 84, \sigma = 15

Sample of 188

This means that n = 188, s = \frac{15}{\sqrt{188}}

What is the probability that the sample mean would differ from the population mean by greater than 1.46 WPM?

Greater than 84 + 1.46 = 85.46 or less than 84 - 1.46 = 82.54. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Probability is is less than 82.54.

P-value of Z when X = 82.54. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{82.54 - 84}{\frac{15}{\sqrt{188}}}

Z = -1.33

Z = -1.33 has a p-value of 0.0918

2*0.0918 = 0.1836

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

3 0
3 years ago
Show work plz
Mazyrski [523]
So first we need to get rid of that naughty sales tax so we need to divide 30.45 by 1.05 since 30.45 is 105% of the pre-tax price. We get the answer of 29 and subtract 12 from 29 since the long fleece socks cost 12 bucks and we get 17 dollars. Since there are 2 pairs of regular songs we divide 17 by 2 and get 8.5

So the regular socks cost $8.50

Checking work 8.5*2=17
12+17=29
1.05*29=30.45

If u need more help feel free to ask me
3 0
3 years ago
Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = π/ 2 ?
Aneli [31]
That answer was (B)................
3 0
3 years ago
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