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Vedmedyk [2.9K]

3 years ago

7

Madyson borrows $1,200 from her father to purchase airplane tickets. The first week after borrowing the money, Madyson repays he

r father $50. Each week after that, she is able to repay her father $2 more than the previous week, except in the last week, when she finishes repaying the loan. How much is Madyson’s final payment?

1 answer:

S_A_V [24]3 years ago

8 0

Her final payment is 78$. Just do 50+52+54+56+58... and so on until you get up into the 1,100's. Then subtract that last number you got from 1200. The answer is 78.

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(Please Help!) Find the radius of a circle so that its area and circumference have the same value.

Lapatulllka [165]

Answer:

the radius must equal 2

Step-by-step explanation:

A = pi * r^2 C = 2 * pi *r

set them equal

pi * r^2 = 2 * pi *r

divide both sides by pi

r^2 = 2 * r

divide both sides by r

r^2 /r = 2r/r

r = 2

4 0

3 years ago

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

Sunny_sXe [5.5K]

Answer:

<h2> $\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$ </h2>

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)}$

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

$\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}$

Distribute -x through the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x }{x(x - 3)(x + 3)}$

Using ${a}^{2} - {b}^{2} = (a + b)(a - b)$ , simplify the product

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)}$

Collect like terms

$\frac{ {x}^{2} + 7x + 15 - 5}{x( {x}^{2} - 9)}$

Subtract the numbers

$\frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)}$

Distribute x through the parentheses

$\frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x}$

Write 7x as a sum

$\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }$

Factor out X from the expression

$\frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x}$

Factor out 2 from the expression

$\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }$

Factor out x + 5 from the expression

$\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$

Hope this helps...

Best regards!!

6 0

3 years ago

Read 2 more answers

The number of typing errors made by a typist has a Poisson distribution with an average of two errors per page. If more than two

wlad13 [49]

Answer: 0.6767

Step-by-step explanation:

Given : Mean = $\lambda=2$ errors per page

Let X be the number of errors in a particular page.

The formula to calculate the Poisson distribution is given by :_

$P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$

Now, the probability that a randomly selected page does not need to be retyped is given by :-

$P(X\leq2)=P(0)+P(1)+P(2)\\\\=(\dfrac{e^{-2}2^0}{0!}+\dfrac{e^{-2}2^1}{1!}+\dfrac{e^{-2}2^2}{2!})\\\\=0.135335283237+0.270670566473+0.270670566473\\\\=0.676676416183\approx0.6767$

Hence, the required probability :- 0.6767

6 0

3 years ago

Is the product of two integers positive, negative, or zero? How can you tell?

marishachu [46]

Answer:

When you multiply a negative number by a positive number then the product is always negative. When you multiply two negative numbers or two positive numbers then the product is always positive. 3 times 4 equals 12. Since there is one positive and one negative number, the product is negative 12.

Step-by-step explanation:

3 0

3 years ago

I need help with some geometry work, there’s a pic x

avanturin [10]

Answer:

it is congruent by SAS axiom

So go with option A

Congruent -SAS

Hope it will help :)❤

3 0

3 years ago