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ryzh [129]
3 years ago
6

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
2 answers:
svp [43]3 years ago
8 0

Points are

  • (-4,-1)
  • (-2,1)
  • (1,-2)
  • (4,-4)
  • (2,4)

All x values has a unique image in y so it's a function

\\ \sf\longmapsto D_f=\{-4,-2,1,4,2\}

\\ \sf\longmapsto R_f=\{-1,1,-2,-4,4\}

quester [9]3 years ago
3 0

Answer:

<u>The domain is the set of x-values:</u>

  • {-4, -2, 1, 2, 4}

<u>The range is the set of y-values:</u>

  • {-4, -2, -1, 1, 4}

This can be a function as each x- value has exactly one corresponding y- value.

You might be interested in
An open metal tank of square base has a volume of 123 m^3
snow_lady [41]

Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

__

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

__

c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

__

d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

3 0
2 years ago
Approximate the square root of 77
GarryVolchara [31]

Answer:

abt 8.77

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
erik drove 439.92 miles on 15.6 gallons of gas. To the nearest hundredth, how many miles could he drive on 39.7 gallons of gas?
Thepotemich [5.8K]
In the question it is already given that Eric drove for 439.92 miles on 15.6 gallons. It is required to find the distance traveled on 39.7 gallons of gas. Also we have to find the answer to the nearest hundredth.
Then,
In 15.6 gallons Eric can drive for a distance = 439.92 miles
In 39.7 gallons Eric can drive for a distance = [(439.92/15.6) * 39.7] miles
                                                                       = 1119.54 miles
So the total distance traveled by Eric is 1120 miles with 39.7 gallons of gas. The answer has been calculated to the nearest hundredth.
6 0
3 years ago
on the first day of a trip, Ricky drove 800 miles in 20 hours. At that rate, how many miles did he drive in 1 hour?
mr Goodwill [35]

We are trying to find miles/hour, which shows that we are going to be dividing the total number of miles by the total number of hours. Thus, in this case, the miles/hour rate will be:

\dfrac{800 \,\textrm{miles}}{20 \,\textrm{hours}} = 40 \dfrac{\textrm{miles}}{\textrm{hour}}


He drove 40 miles in one hour.

7 0
3 years ago
Read 2 more answers
Financial Mathematics Discussion Board Prompt:
yarga [219]

Answer:

Younger oiiiiiiiiiiii

7 0
2 years ago
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