Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Answer:
TRY
MET
GET
YET
METRO
MORE
This is all i got :)
Step-by-step explanation:
Answer: Graph A
Step-by-step explanation:
Answer:
400$
Step-by-step explanation:
Let C.P. of the watch = Rs. 100
When profit =5%; S.P. = Rs. (100+5)
= Rs. 105
and when profit = 11%;
S.P. = Rs. (100+11)
=Rs.111
Difference of two selling prices
= Rs. 111-Rs.105 = Rs.6
When watch sold for Rs. 6 more; then C.P. of the watch = Rs.
100
6
When watch sold for Rs. 24 more; then C.P. of the watch = Rs.
100
6
×
24
= Rs.
100
×
24
6
=400
The factoring can be done similarly to a quadratic equation thanks to x^4 being the square value of x^2.
<span>x^4 + 6x^2 - 7
x^4</span><span> - x^2</span> + 7x^2 - 7
(x^4 - x^2) + (<span>7x^2 - 7)
</span>x^2(x^2 - 1) + 7(<span>x^2 - 1)
</span>(x^2 + 7)(x^2 - 1)
<span>(x^2 + 7)(x - 1)(x + 1)
</span>
Factored completely we get: <span>(x^2 + 7)(x - 1)(x + 1)</span>
