Answer:
A
Step-by-step explanation:
Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
Answer:
LIMIT
The policy will pay for up to
$100,000 of damage to
another person's property.
The policy will pay only
$100 per incident for a
tow truck
DEDUCTIBLE
The policyholder must pay
the first $1,000 of repair
expenses before insurance
will pay for anything,
PREMIUM
The policy offers coverage
for a cost of $178 per month
The policyholder must
pay $500 semiannually
to the insurance provider
Step-by-step explanation:
LIMIT is the maximum amount an insurer will pay toward a covered claim
DEDUCTIBLE is the amount paid out of pocket toward a covered claim
PREMIUM is the amount paid regularly to keep the policy in force.
Area=(base x height)/2
base=5.8 cm
height=2.4 cm
Area=(5.8 cm * 2.4 cm) / 2=6.96 cm²
The answer is A 6.96