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ziro4ka [17]
3 years ago
6

Quick please help. what is the missing value of y-4=-2(x+3)y−4=−2(x+3)

Mathematics
1 answer:
Reil [10]3 years ago
3 0

Answer:

fiduciary bin tashfeen Ivey on ppl cindy no

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Step-by-step explanation:

A parallel line will have the same slope as the reference line.  In this case, I don't see the "given line" as promised in the question.  If it does appear, and it looks like y = 5x + 3, for example, the slope is 5 and the new line will have the same slope.

<h3><u>If this slope is correct</u>, we can start the equation for the parallel line that goes through point (-3,2) by starting with:</h3><h3 /><h3>y = 5x + b</h3><h3 /><h3>We need a value of b that forces the line to go through point (-3,2).  We can do that by using the given point in the equation and solving for b:</h3><h3>y = 5x + b</h3><h3>2 = 5(-3) + b</h3><h3>b = 17</h3><h3 /><h3>The parallel line to y=5x+3 is</h3><h3>y = 5x + 17</h3><h3 /><h3>See attachment.</h3><h3 /><h3 /><h3 />

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To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y. ...
To find the x-intercept, set y = 0 \displaystyle y=0 y=0.
To find the y-intercept, set x = 0 \displaystyle x=0 x=0.


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3 years ago
Read 2 more answers
Help is very much appreciated!
mote1985 [20]

Answer:

Step-by-step explanation:

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