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bulgar [2K]
3 years ago
6

Simplify the expression without solving for x 8x +4-3-x=

Mathematics
2 answers:
marissa [1.9K]3 years ago
4 0
Answer: 7x + 1

Explanation:
First you need to organize each integer with the variable at its ending.
8x, -x both have the x variable
+4, -3 both are regular integers
8x - x = 7x
4 - 3 = 1
So it’s 7x - 1
Anna35 [415]3 years ago
4 0
8x+4-3-x=
8x-x=7x
4-3=1
7x+1
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What are the real zeroes of x3 + 6 x2 – 9x - 54?
o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

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Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

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7 0
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