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Vinvika [58]
4 years ago
11

Roger mixed 5/8 cup of red paint with 2/5 cup of yellow paint. How much red paint is needed (using the same ratio) if he wants t

o use 1 cup yellow paint
Mathematics
1 answer:
never [62]4 years ago
5 0
Set up the ratio as fractions

(5/8) cup red / (2/5) cup yellow = r amount of red / 1 cup yellow

Then cross multiply the numbers and set up as a equation like this

(5/8) × 1 = (2/5) × r

(5/8) = (2/5)r

Multiply both sides of the equation by (5/2) to get rid of the fraction and solve for r

(5/2) × (5/8) = (2/5)r × <span>(5/2)

25/16 = r

Reduce down to 5/4 or change to a mixed number

1 and 1/4  cups = r</span>
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A card is selected at random from an ordinary deck of 52 cards. What is the probability that it is either an ace or a spade
tamaranim1 [39]

Answer: 4/13

Step-by-step explanation:

Number of cards in a deck = 52

Number of spades = 13

Number of aces = 4

Number of ace of spade = 1

Probability of either a spade or an ace :

P(spade or ace) = P(spade U ace)

P(spade U ace) = p(spade) + p(ace) - p(spade n ace)

Probability = required outcome / Total possible outcomes

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P(spade n ace) = 1 / 52

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= 13/52 + 4/52 - 1/52

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3 years ago
X³ by a³ + a³by x³=p x³by a³- a³by ³=q eliminate x
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Answer:

Step-by-step explanation:

\frac{x^3}{a^3} +\frac{a^3}{x^3} =p\\\frac{x^3}{a^3} -\frac{a^3}{x^3} =q\\adding\\2\frac{x^3}{a^3} =p+q\\\frac{x^3}{a^3} =\frac{p+q}{2} \\substitute~in~first\\\frac{p+q}{2} +\frac{2}{p+q} =p\\\frac{(p+q)^2+4}{2(p+q)} =p\\(p+q)^2+4=2p(p+q)\\p^2+q^2+2pq+4-2p^2-2pq=0\\q^2-p^2+4=0\\q^2=p^2-4

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Answer:

2S + J = 24000

Step-by-step explanation:

let Susan be S

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susan paid twice as muh as jinan did​

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2S + J = 24000

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