Suppose a box contains 3 defective light bulbs and 12 good bulbs. two bulbs are chosen from the box without replacement. find th

Question

MakcuM [25]

3 years ago

6

Suppose a box contains 3 defective light bulbs and 12 good bulbs. two bulbs are chosen from the box without replacement. find th

e probability that one of the bulbs drawn is good and one is defective.

Mathematics

1 answer:

Mademuasel [1] · Answer 1 · 2021-12-27T13:40:03+03:00

Mademuasel [1]3 years ago

7 0

The probability that the bulb is good is 12/15.
Since we have taken 1 item out the remaining total is now 14, so the probability of getting a defective bulb is now 3/14.
Now you multiply the probabilities together to get (12/15)(3/14)=(4/5)(3/14)=12/70=6/35