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MakcuM [25]
3 years ago
6

Suppose a box contains 3 defective light bulbs and 12 good bulbs. two bulbs are chosen from the box without replacement. find th

e probability that one of the bulbs drawn is good and one is defective.
Mathematics
1 answer:
Mademuasel [1]3 years ago
7 0
The probability that the bulb is good is 12/15.
Since we have taken 1 item out the remaining total is now 14, so the probability of getting a defective bulb is now 3/14.
Now you multiply the probabilities together to get (12/15)(3/14)=(4/5)(3/14)=12/70=6/35
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