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MakcuM [25]
3 years ago
6

Suppose a box contains 3 defective light bulbs and 12 good bulbs. two bulbs are chosen from the box without replacement. find th

e probability that one of the bulbs drawn is good and one is defective.
Mathematics
1 answer:
Mademuasel [1]3 years ago
7 0
The probability that the bulb is good is 12/15.
Since we have taken 1 item out the remaining total is now 14, so the probability of getting a defective bulb is now 3/14.
Now you multiply the probabilities together to get (12/15)(3/14)=(4/5)(3/14)=12/70=6/35
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-288

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(4 + 32)(15 – 23)

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2 years ago
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Deffense [45]

Answer:

the scale factor is 3/4

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Step-by-step explanation:

the only side length we have for both triangles is the short left side.

we see that we get ED from SR and need to transform 4 into 3. how do we do that ?

well,

4×f = 3

f = 3/4

that is the scaling factor, as all side lengths in EDF are created by multiplying the corresponding side in SRT by the same scaling factor (3/4).

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x = EF = ST×f = 16×3/4 = 4×3 = 12

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3 years ago
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antoniya [11.8K]

b - 6/8

is the answer

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3 years ago
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