Y = -x^2 + x + 2
y = -x + 3
-x + 3 = -x^2 + x + 2
x^2 - x - 2 - x + 3 = 0
x^2 -2x + 1 = 0
(x - 1)(x - 1) = 0
x - 1 = 0 y = -x + 3
x = 1 y = -1 + 3
y = 2
solutions are : (1,2) , (1,2)
The negative would be 12-14 witch = -2
(2x - 8) - (4x + 8)
first look at the x
2x - 4x = -2x
-2x is left over
then look at the numbers
8 - (-8)
in the case of having two negatives, it becomes positive, and so it is really 8 + 8
8 + 8 = 16
-2x - 16 is your answer
hope this helps
Answer:
57
Step-by-step explanation:
I prefer the equation in this format

substitute -4 for m and 6 for n

square the 6 then multiply by 2

solve inside the absolute value then multiply by 3


divide by 4
