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andrew-mc [135]
3 years ago
7

Two times a number plus 5 equals 25. What is the number?

Mathematics
2 answers:
sergeinik [125]3 years ago
8 0
This is actually very simple to figure out. What times 2 equals 20? The answer is 10. 10 times 2 equals 20. Add the 5, and you have 25.
Your answer is 10
Svetlanka [38]3 years ago
3 0
The number is ten. hope it helps

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Step-by-step explanation:

Given: The commuting time on a particular train is uniformly distributed over the interval (42,52).

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f(x)=\dfrac{1}{b-a}\\\\=\dfrac{1}{52-42}=\dfrac{1}{10}, 42

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3 years ago
If 3X + 2 equals 11, could X equal 5
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Answer:

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Step-by-step explanation:

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Answer:

a)Reflexive, not symmetric, transitive

b)Reflexive, not symmetric, transitive

c)Not reflexive, symmetric, not transitive

d)Reflexive, not symmetric, transitive

Step-by-step explanation:

a)

R=\left \{ (a,b)\epsilon  \mathbb{R} \times \mathbb{R} \mid a \leq b\right \}

The relation R is reflexive for

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it is not symmetric because 0 is less than 1, but 1 is not less than 0

it is transitive

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b)  

R=\left \{ (m,n)\epsilon  \mathbb{Z} \times \mathbb{Z} \mid \exists k\in \mathbb{Z} \ni m=kn \right \}

R is reflexive because m=1.m for every integer m

R is not symmetric: 2 is a factor of 4, but 4 is not a factor of 2

R is transitive:  if mRn and nRp if m=kn and n=qp, so m=(kq)p and kq is an integer , so mRp

c)

R=\left \{ (m,n)\epsilon  \mathbb{Z} \times \mathbb{Z} \mid m\neq n\right \}

R is obviously not reflexive because all numbers equals themselves

R is symmetric: if a different to b, then b different to a

R is not transitive: 1R2 and 2R1 (because 1 different to 2), but 1 = 1

d)

R=\left \{ A,B\mid A\subseteq B \right \}

R is reflexive for every set A is a subset of itself

R is not symmetric {1,2} is a subset of {1,2,3} but {1,2,3} is not a subset of {1,2}

R is transitive: if A is subset of B and B is subset of C, then A is subset of C

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