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zhenek [66]
3 years ago
6

I dont know what it is

Chemistry
2 answers:
Lisa [10]3 years ago
8 0
Carbon
Hydrogen
Oxygen
Nitrogen 
Sulfur
Sodium
Phosphorus
Iron
Calcium
marysya [2.9K]3 years ago
5 0
Carbon
calcuim
iron
hydrogen
iodine
nitrogen
oxygen
phosphorus
sulfur
The letters are the symbols for those elements
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dalvyx [7]
It is either Slate, Phyllite, Schist, and or Gneiss 
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Abiotic factors in an environment include A) producers. B) decomposers. C) predators and prey. D) sunlight and water. Abiotic fa
Oliga [24]

Answer:

Sunlight and water (D)

Explanation:

Sunlight and water are two of the many abiotic factors that may be present in a particular environment. All other factors mentioned in the choices are biotic factors. Producers are plants; decomposers are fungi and bacteria

5 0
3 years ago
Calculate the mass (in g) of 2.1 x 1024 atoms of W.
vfiekz [6]
Set up your units to algebraically cancel out the original unit, and end up with the units of the answer in the final numerator. We'll first convert to moles by using Avogadro's number, then the atomic mass of tungsten (W) from the periodic table, since the mass, in grams, of one mole of any element is the atomic mass number:
2.1x10∧24 atoms W x (1 mole/6.022x10∧23 atoms) x (183.84g/1 mole) = 641.089 grams
Since your given number has only two significant figures (2.1), your answer should also only express in 2 sig figs: 6.4x10∧2 grams

6 0
3 years ago
What defines the mass number of an isotope
vekshin1
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For instance Carbon-13 is an isotope of carbon. The "13" is the mass number of the isotope.
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8 0
4 years ago
Calculate the solubility of copper (II) iodate in 0.16 M copper (II) nitrate. Ksp* is 7.4x10-8 M3. *You should know that the Ksp
Simora [160]

Answer:

solubility in presence of 0.16M Cu(IO₃⁻)₂ = 3.4 x 10⁻⁴M*

Explanation:

        Cu(IO₃⁻)₂ ⇄           Cu⁺²          +   2(IO₃⁻)        

C(i)    ----------                0.16M                 0M

ΔC    ----------                   +x                   +2x

C(f)    ----------      0.16 + x ≅ 0.16M*        2x

Ksp = [Cu⁺²][IO₃⁻]²

7.4 x 10⁻⁸M³ = 0.16M(2x)² = 0.64x²

x = solubility in presence of 0.16M Cu(IO₃⁻)₂ = SqrRt(7.4x10⁻⁸M³/0.64M²)

= 3.4 x 10⁻⁴M*

*Note: This is consistent with the common ion effect in that a reduction in solubility is expected. The normal solubility of Cu(IO₃⁻)₂ in pure water at 25°C is ~2.7 x 10⁻³M.

3 0
3 years ago
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