Answer : The standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The combustion of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
Now we are reversing reaction 1 and then adding both the equations, we get :
(1) 
(2)
The expression for enthalpy change for the reaction will be,
Therefore, the standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol
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Answer:
A. All the molecules or atoms in motion have kinetic energy.
B. All the molecules or atoms in motion have thermal energy.
C. Each molecule or atom in motion has thermal energy.
D. Each molecule or atom in motion has kinetic energy.
Explanation:
<span>The root mean square speed is given by V_rms = âšRT/M where r, t, and m are the rate constant, temperature and molar mass the gas
Average molar kinetic energy of the gas
E = 1/2 M * (V_rms)^2 = 8750 ms/1
So (V_rms)^2 = (2 * 8750) / M
Molar mass of 2 chlorine atoms in kg is 2 * 35 * 10^(-3)
Hence we have (V_rms)^2 = (2 * 8750)/ (2 * 35 * 10^(-3))
(V_rms)^2 = 8750/0.035 = 250000
So V_rms = âš 250000 = 500</span>
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