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3 years ago

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Steve's doctor has advised him to take protein supplements. He bought two brands, Brand A and Brand B. The table gives the amoun

t of calcium, iron, and vitamins (in milligrams per spoonful) in each of the two brands.

1 answer:

BlackZzzverrR [31]3 years ago

6 0

Here s the question this is the doc i put it on please help

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Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

7 0

3 years ago

SUPER EASY WILL UPVOTE Create a number sequence in which the first term is 4. Explain the pattern that you used.

Darya [45]

The sequence is 4, 5, 6, 7, 8, ..... The pattern is: Each term is (the term before it) plus (1).

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3 years ago

The difference between two positive integers is 54. One integer is three times as great as the other. Find the integer

sveta [45]

The answer is 27
27+54=81 and 27x3= 81
:)

7 0

3 years ago

5x +3 <br> ____ = -9 plz help these are impossible!!<br> -2

kiruha [24]

My work is shown up above in the picture.

4 0

3 years ago

Read 2 more answers

A past study claims that adults in America spend an average of 17 hours a week on leisure activities. A researcher wanted to tes

8090 [49]

Answer:

The claim is false.

Step-by-step explanation:

Given the data :

13 24 21 37 15 25 18 22 40 32

The sample mean and standard deviation can ben calculated for the given sample.

Using calculator :

Sample mean, xbar = 24.7

Sample standard deviation, s = 9.04

Sample size, n = 10

The hypothesis :

H0 : μ = 17

H1 : μ ≠ 17

The test statistic :

(xbar - μ) ÷ (s/√(n))

(24.7 - 17) ÷ (9.04/√(10))

7.7 / 2.8586990

Test statistic = 2.694

We can obtain the Pvalue, at α = 0.05 ; df = n-1 = 9

Pvalue = 0.0246

Since Pvalue < α ; we reject the null ; Hence, there is significant evidence to conclude that an adult American does not spend average of 17 hours in leisure

5 0

3 years ago