Choice C for problem 6 is correct. The two angles (65 and 25) add to 90 degrees, proving they are complementary angles.
===========================================
The answer to problem 7 is also choice C and here's why
To find the midpoint, we add up the x coordinates and divide by 2. The two points A(-5,3) and B(3,3) have x coordinates of -5 and 3 respectively. They add to -5+3 = -2 which cuts in half to get -1. This means C has to be the answer as it's the only choice with x = -1 as an x coordinate.
Let's keep going to find the y coordinate of the midpoint. The points A(-5,3) and B(3,3) have y coordinates of y = 3 and y = 3, they add to 3+3 = 6 which cuts in half to get 3. The midpoint has the same y coordinate as the other two points
So that is why the midpoint is (-1,3)
First make the 2 fractions to one common denominator,
10/40 and 8/40 and add them,
10/40 + 8/40 = 18/40
simplified, 9/20
answer- 9/20 of the pizza
Answer:
a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90
a= μ-3.16*σ , b= μ+3.16*σ
b) P(Y≥ μ+3*σ ) ≥ 0.90
b= μ+3*σ
Step-by-step explanation:
from Chebyshev's inequality for Y
P(| Y - μ|≤ k*σ ) ≥ 1-1/k²
where
Y = the number of fish that need be caught to obtain at least one of each type
μ = expected value of Y
σ = standard deviation of Y
P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean
k= parameter
thus for
P(| Y - μ|≤ k*σ ) ≥ 1-1/k²
P{a≤Y≤b} ≥ 0.90 → 1-1/k² = 0.90 → k = 3.16
then
P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90
using one-sided Chebyshev inequality (Cantelli's inequality)
P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)
P{Y≥b} ≥ 0.90 → 1- σ²/(σ²+λ²)= 1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ
then for
P(Y≥ μ+3*σ ) ≥ 0.90
First, draw a diagram of a kite with sides GHIJ. The sides GH, HI, IJ, and JG are the sides. The diagonals can be determined by connecting the opposite sides. J and H, G and I. Therefore, the diagonals for the Kite GHIJ is JH and GI.
Answer: 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17
Step-by-step explanation:
First, we can ensure that 12 is the median by putting it in the middle and putting the same amount of numbers to its left and right side. To make the values have a mean of 12, the easy why to do it is to subtrate one as you move to the left and add one as you move to the right, that way they will cancel each other out and keep the mean at 12. The answer has a total of 11 values, has more than 3 values that are different, and has a mean and median of 12.
7+8+9+10+11+12+13+14+15+16+17=132
132/11=12
There are 5 values to each side of 12, making 12 the median.
