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lisov135 [29]
4 years ago
9

PLEASE HELP Jackie has set up a lemonade stand this summer. The line plot represents how many liters she has sold during her fir

st 13 days in business. How much lemonade has Jackie sold in all?
Mathematics
1 answer:
IRISSAK [1]4 years ago
3 0
There's no line plot here :(
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possibility 1: 8/10x 2/9 x 1/8 = 16/720=1/45
possibility 2: 2/10 x 8/9 x 1/8= 16/720=1/45

answer: 2/45
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If 5(3x-1)=55 what is the value of 2x-2
cricket20 [7]

Hey ! there

Answer:

  • Value of 2x - 2 is <u>6</u><u> </u><u>.</u>

Step-by-step explanation:

In this question we are provided with an equation that is <u>5</u><u> </u><u>(</u><u> </u><u>3x</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>5</u><u>5</u><u> </u>and we are asked to find the value of <u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>.</u>

Firstly , we need to find the value of x . So we need to solve the equation .

<u>SOLUTION</u><u> </u><u>:</u><u> </u><u>-</u>

\quad \longmapsto \qquad \: 5(3x - 1) = 55

<u>Step </u><u>1</u><u> </u><u>:</u> Dividing with 5 on both sides :

\quad \longmapsto \qquad \: \dfrac{ \cancel{5}(3x - 1)}{ \cancel{5}}  = \cancel{\dfrac{55}{5} }

On cancelling , We get :

\quad \longmapsto \qquad \:3x - 1 = 11

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 1 on both sides :

\quad \longmapsto \qquad \:3x -  \cancel{1} +  \cancel{1} = 11 + 1

On simplifying , We get :

\quad \longmapsto \qquad \:3x = 12

<u>Step </u><u>3 </u><u>:</u> Dividing with 3 on both sides :

\quad \longmapsto \qquad \: \dfrac{ \cancel{3}x}{ \cancel{3}}  =  \cancel{ \dfrac{12}{3} }

We get ,

\quad \longmapsto \qquad \:    \underline{\boxed{\frak{x = 4}}}

→ Therefore , value of x is <u>4</u><u> </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are verifying whether our answer is wrong or right . So ,

  • 5 ( 3x - 1 ) = 55

  • 5 { 3( 4 ) - 1 } = 55

  • 5 ( 12 - 1 ) = 55

  • 5 ( 11 ) = 55

  • L.H.S = R.H.S

  • Hence , Verified .

Therefore , our value of x is <u>correct</u><u>/</u><u>valid </u><u>.</u>

<u>We </u><u>need </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>.</u><u> </u>

<u>\quad \longmapsto \qquad \:2x - 2</u>

So substituting value of x in it :

<u>\quad \longmapsto \qquad \:2( \bold{4}) - 2</u>

Multiplying 2 with 4 :<u> </u>

<u>\quad \longmapsto \qquad \:8 - 2</u>

Subtracting 2 from 8 :

\quad \longmapsto \qquad \:    \blue{\underline{\boxed{\frak{6}}}}  \quad \: \bigstar

  • <u>Henceforth</u><u>,</u><u> </u><u>value </u><u>of </u><u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>is </u><u>❝</u><u> </u><u>6</u><u> </u><u>❞</u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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27-14=c

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