The answer is 0.00125139043
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
The < and > signs mean lesser and greater than. = means equal(s). The signs will always look like they are eating the bigger value. For example:
12<29
Twelve is lesser than twenty-nine, or
29>12
Twenty-nine is greater than twelve.
An equation uses an equal sign
12+8=20
When you're using all of them, it can look like this:
1<n<29
This is read as "one is lesser than n which is lesser than 29". These can be used to determine the lengths of the sides of a triangle. In this case, n must be between 1 and 29 for it to be the side of a triangle.
Answer:
48x − 12y−3
Step-by-step explanation:
Distribute:
(6)(8x) + (6)(−2y) + −3
48x + −12y + −3
48x − 12y−3
