3 years ago

Which choice is equivalent to the product below? Square root of 8 Times Square root of 3

Mathematics

1 answer:

olga55 [171]3 years ago

7 0

Answer:

The equivalent would be the square root of 24, which can also be written as 2 times the square root of 6.

Step-by-step explanation:

To find that we can simply multiply the two numbers under the square root symbol and then express them as a square root.

3* 8 = 24

You might be interested in

Please help I'll give brainliest

Liula [17]

the answer is going to be 6.0

Step-by-step explanation:

1.5 + 1.5 = 3

3 + 3 = 6

6 0

3 years ago

How do you solve 3x^6- 39x^4+ 108x^2= 0

ArbitrLikvidat [17]

You can first take out an x^2 from each number , 3x^6 - 39x^4 + 108x^2 = x^2 ( 3x^4 - 39x^2 + 108) Then just factor and solve for the zero's of the equation

6 0

3 years ago

Evaluate the piecewise function by matching the domain values with the range values

belka [17]

Answer:

What are the rangle and domain values

Step-by-step explanation:

5 0

3 years ago

Evaluate the expression.<br> -6+3(-3+7).

lesantik [10]

Answer:

answer for this question is 6

3 0

3 years ago

Read 2 more answers

PLSSS<br><br> C= <img src="https://tex.z-dn.net/?f=%5Cfrac%7B12%5E%7B3%7D%20.%206%5E%7B5%7D%20%7D%7B9%5E%7B4%7D%20.%202%5E%7B10%

Rudiy27

Answer:

Step-by-step explanation:

The trick here is to reduce each of the bases to lowest form first

$12 = 3.4 = 3 .2.2 = 3.2^{2}\\12^{3} = (3.2^{2} )^{3} = 3^{3}2^{6} \\6 = 3.2\\6^{5} = (3.2)^{5} = 3^{5} .2^{5} \\\\Numerator = 3^32^63^52^5 = 3^82^{11}\\Denominator computation\\9 = 3^2\\9^{4} = (3^{2} )^4 = 3^{8} \\Denominator = 3^82^{10} \\\\\frac{Numerator}{Denominator } =\frac{{3^8}{2^{11} }}{3^82^{10}} = \frac{2^{11}} {2^{10}} = 2^1 = 2$

7 0

2 years ago