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3 years ago

ASAP MATH HELP PLEASE!!!

Mathematics

1 answer:

fenix001 [56]3 years ago

5 0

13. D

14. D

15. B

adding more words just to post this...lol

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Flying against the jetstream, a jet travels 4960 miles in 8 hours. Flying with the jetstream, the same jet travels 2940 miles in

oksian1 [2.3K]

Answer:

Velocity of jet in still air is 800mph hour and velocity of wind is 180mph

Step-by-step explanation:

Let the velocity of jet in still air be x miles per hour and velocity of wind be y miles per hour.

#Jet's velocity against jet-stream is:

$v_i=\frac{4960}{8}\\\\=620\ mph$

#Jet's velocity with jet-stream:

$v_{ii}=\frac{2940}{3}\\\\=980\ mph$

#The velocity against jet-stream is x-y and with jet-stream is x+y:

$x-y=620\\\\x+y=980\\\\\#add \ the \ two \ equations\ to \ eliminate \ y\\\\2x=1600\\\\x=800\\\\y=980-800=180$

Hence,velocity of jet in still air is 800 mph hour and velocity of wind is 180 mph.

3 0

3 years ago

What is the answer for -5a - 12a simplify

USPshnik [31]

-5a - 12a can also be rewritten as:

-5a + -12a, which would equal -17a

4 0

4 years ago

Read 2 more answers

Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for th

NeX [460]

As long as Loren drove, the law of motion was

$200 = st_1 \implies t_1 = \dfrac{200}{s}$

As long as Loid drove, the law of motion was

$100 = (s-10)t_2 \implies t_2 = \dfrac{100}{s-10}$

So, the total time they took is

$t_1+t_2=\dfrac{200}{s}+\dfrac{100}{s-10}$

Had Loren driven the whole time, the law of motion would have been

$300=st_3 \implies t_3 = \dfrac{300}{s}$

And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have

$t_3 = t_1+t_2-0.5$

This translates into

$\dfrac{300}{s}=\dfrac{200}{s}+\dfrac{100}{s-10}-\dfrac{1}{2}$

If we subtract 200/s from both sides, we have

$\dfrac{100}{s}=\dfrac{100}{s-10}-\dfrac{1}{2}$

We can simplify the right hand side by summing the two fractions:

$\dfrac{100}{s-10}-\dfrac{1}{2} = \dfrac{200-(s-10)}{2(s-10)}=\dfrac{210-s}{2(s-10)}$

So, we have to solve

$\dfrac{100}{s}=\dfrac{210-s}{2(s-10)}$

If we cross multiply the denominators, we have

$200(s-10)=s(210-s) \iff 200s-2000=210s-s^2 \iff s^2-10s-2000=0$

Which yields the solutions

$s=-40,\quad s=50$

We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph

5 0

3 years ago

Read 2 more answers

the inequality 2p<18 can be used to determine how many pounds of apples at $2.00 per pound ,p, you can buy while spending $18

babunello [35]

You could buy 9 pounds without exceeding your 18 dollar limit. You would solve it buy dividing the 18 by 2 to get your answer

6 0

3 years ago

Pls help asap!!!!!!!

xeze [42]

Answer:

$3\cdot \frac{1}{2},\:\frac{21}{7},\:\pi ,\:4.1$

Step-by-step explanation:

convert the number to all decimals or fraction and compare.

4 0

2 years ago