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Reika [66]
4 years ago
9

Which figure represents an undefined term?

Mathematics
1 answer:
notka56 [123]4 years ago
8 0
In geometry, an undefined term is a basic figure that cannot be defined in terms of other figures.
The undefined terms in geometry are: point, line and plane.

Since you have not attached any figures, I cannot tell you which one is correct. Just choose the figure that is either a point, a line or a plane.
You might be interested in
Question 1
horsena [70]

Answer:

diameter(d)=8 in.

radius(r)= d/2= 4 in.

height(h)= 3r = 3(4) = 12 in.

Volume=r ² h

          =(3.14)(4)²(12)

          =(3.14)(16)(12)

          =602.88 in.

   

      Therefore, the volume of the cylinder is 602.88 in.

Step-by-step explanation:

8 0
3 years ago
If 1/2 of a loaf of brown bread costs R6,how much will 2 halves cost​
dimulka [17.4K]

Step-by-step explanation:

1/2 is equal to R6.

So 2 halves mean R6+R6=R12

Or

R6×2= R12

Answer:R12

5 0
3 years ago
-k^2-(4k-9n)+6n; k= -3 and n= -2
dalvyx [7]

Answer:

\displaystyle -27

Step-by-step explanation:

\displaystyle -[-3]^2 - [4(-3) - 9(-2)] + 6[-2] \hookrightarrow -9 - [-12 + 18] - 12 \hookrightarrow -9 - 6 - 12 \\ \\ \boxed{-27}

I am joyous to assist you at any time.

6 0
3 years ago
A circle is centered at Q(1,-5) and has a radius of 5.<br> Where does the point Y (4,1) lie?
Svetradugi [14.3K]

Answer:

The point lies outside the circle.

Step-by-step explanation:

<u>To find where the point lies find the distance between the centre of the circle and the point :</u>

<u />Distance , QY = \sqrt{(4-1)^2 + (1-(-5))^2}<u />

                     = \sqrt{3^2 + 6^2}\\\\= \sqrt{9 + 36 }  \\\\= \sqrt{45}  = 6.71

Since distance between Centre, Q and the point, Y is greater than the radius of the circle , the point lies outside the circle.

8 0
3 years ago
3. The angles of elevation to an airplane from two points A and B on level ground are 55o and 72o respectively. A and B are 2.2
iren2701 [21]

Answer:

CD = 5.9 mi

Step-by-step explanation:

Given:

∠DAC = 55°

∠DBC = 72°

AB = 2.2 mi

∠ABD = 180 - ∠DBC = 180 - 72 = 108°

∠ADB = 180 - ∠BAD - ∠ABD = 180 -55 - 108 = 17°

Using Sine Rule:

\frac{AB}{sin{ADB} } = \frac{BD}{sin{BAD}}

\frac{2.2}{sin{17}} = \frac{BD}{sin{55}}

Solving for BD:

BD = 6.2 mi

From ΔBDC

Sin(72) = CD / BD

Sin(72) = CD / 6.2

Solving for CD:

CD = 6.2*sin(72) = 5.9 mi

6 0
3 years ago
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