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3 years ago

Which absolute value function, when graphed, will be

Mathematics

1 answer:

lara [203]3 years ago

6 0

Answer: f(x) = (1/3)*IxI

Step-by-step explanation:

Ok, this is a problem of transformations.

First, if we have f(x), then:

f(x - a) is a translation of a units in the x-axis

f(x) + a is a translation of a units in the y-axis.

a*f(x) is a dilation/contraction.

if a is greater than 1, then the graph will be steeper (less wide)

if a is smaller than 1, then the graph will be wider.

Looking at the options, the correct option is:

f(x) = (1/3)*IxI

where we can see that a = (1/3)

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2 years ago

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3 years ago

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

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$AC = \sqrt{74}$

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8 0

3 years ago

In the figure below, if the radius of circle o

Aliun [14]

Answer:

The length of AC is 10 units

Step-by-step explanation:

In the given circle O

∵ AOCB is a rectangle

∵ OB and AC are the diagonals of the rectangle AOCB

∵ Diagonals of the rectangle are equal in lengths

→ That means OB and AC are equal in lengths

∴ OB = AC

∵ O is the center of the circle

∵ B is a point on the circle

∴ OB is a radius of the circle O

∵ The radius of the circle is 10 units

∴ OB = 10 units

∵ OB = AC

∴ AC = 10 units

∴ The length of AC is 10 units

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