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VMariaS [17]
3 years ago
10

3/4 ÷ 2 (with calculation shown please?

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0
3/4÷ 2=3/4÷ 2/1=3/4*1/2=3*1/4*2=3/8
The answer is 3/8

just olya [345]3 years ago
3 0
3/4 divided by 2--> change to multiplication reciprocating the second number--> 2/1 into 1/2==now you have 3/4 times 1/2=3/8
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Match the equivalent expressions.
Arte-miy333 [17]

Answer:

see below

Step-by-step explanation:

5(x + y) + 6(x − y)

Distribute

5x+ 5y + 6x -6y

Combine like terms

11x -y

(5x − 3y) − x + 3x − 5y

Combine like terms

5x -x +3x   -3y -5y

7x -8y

4(x + y) − 3(x + y)

Distribute

4x +4y -3x -3y

Combine like terms

x -y

x − 4x + 6y + (14x − 5y)

Combine like terms

x -4x +14x    +6y -5y

11x    +y

3x + 3y + 2(2x − y)

Distribute

3x+3y +4x -2y

Combine like terms

7x +y

7 0
3 years ago
Mark's computer weighs 35.769 pounds.
lawyer [7]

Answer:

you have to round up so it would round up to 35.800

Step-by-step explanation:

6 0
2 years ago
A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc
aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

AC^{2} =AB^{2} +BC^{2}

Substituting the values of BC = 3 and AC = 5, we have,

5^{2} =AB^{2} +3^{2}

Squaring the terms, we get,

25 =AB^{2} +9

Subtracting both sides by 9, we have,

16 =AB^{2}

Taking square root on both sides,

AB = 4

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0
3 years ago
Describe how you would compare 3.6 and <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B12%7D%20" id="TexFormula1" title=" \sq
pogonyaev

Step-by-step explanation:

√12=

2√3

÷2. ÷2

√3. 1.8

√3≈1.7

1.7<1.8

3.6>√12

method 2

(3.6)^2>12

5 0
3 years ago
Read 2 more answers
What is the quotient of 78.3 ÷ 3.48?
olga_2 [115]
The answer is 22.5. I hope this helps you.

Good luck with your work! 
8 0
3 years ago
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