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4 years ago

Rearrange the formula S = a (a - r) for r.

2 answers:

8 0

I'm assuming you're trying to solve for r.
First divide a to both sides
Now you have $\frac{S}{a}$ = a - r
Subtract a to both sides.
And then divide by -1 to both sides.
Now your equation is - $\frac{S}{a}$ + a = r

Black_prince [1.1K]4 years ago

6 0

Expand: a^2 - ar

S= a^2 -ar

S+ ar = a^2

Ar = a^2 - S

R = a^2 - S/ a

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Water flows through a pipe at a rate of 12 cups every 5 hours. Express this rate of flow in gallons per week.

horrorfan [7]

Answer:

Well 403.2 gallons per week

Step-by-step explanation:

So 24*7

168

168/5

33 3/5

33 3/5* 12

403.2

7 0

3 years ago

Complete the sentence.<br> 7 is 1/10 of

Schach [20]

7 is 1/10 of.. 70, because 10 times 7 is 70 :)

5 0

3 years ago

Read 2 more answers

Juan walks 3.5 miles in 56 minutes. How long will it take him to walk 1 mile?

mestny [16]

distance = time * speed

1 mile = time * 3.5 miles /56 minutes

so time = 56 minutes/3.5 = 16 minutes

5 0

3 years ago

Read 2 more answers

Through: (-5, -5), parallel to y = 3/5x + 3

Komok [63]

Answer:

$\displaystyle y=\frac{3}{5}x-2$

Step-by-step explanation:

We want to find the equation of a line parallel to:

$\displaystyle y=\frac{3}{5}x+3$

And passes through (-5, -5).

Recall that parallel lines must have the same slope.

Since the slope of our old line is 3/5, the slope of our new line must also be 3/5.

So, we know that the slope of our new line is 3/5 and it passes through (-5, -5).

Now, we can use the point-slope form given by:

$y-y_1=m(x-x_1)$

We will let (-5, -5) be (x₁, y₁). m is the slope or 3/5. Hence:

$\displaystyle y-(-5)=\frac{3}{5}(x-(-5))$

Simplify:

$\displaystyle y+5=\frac{3}{5}(x+5)$

Distribute:

$\displaystyle y+5=\frac{3}{5}x+3$

Subtract 5 from both sides:

$\displaystyle y=\frac{3}{5}x-2$

And we have our equation.

7 0

3 years ago

Word Problems:

vaieri [72.5K]

Answer:

Andy's Rental Car: f(x)= 20 + (30x)

Buddy's Rental Car: f(x) 36 + (28x)

Step-by-step explanation:

First, identify what you know:

1) Andy's Rental Car charges an initial fee of $20 plus an additional $30 per day to rent a car.

2) Buddy's Rental Car charges an initial fee of $36 plus an additional $28 a day!

So, which rental car company has the better deal? Imagine you want to rent a car for ten days, which would you choose?

First, create an equation for each:

Andy's Rental Car: f(x)= 20 + (30x)

The x represents the number of days the car is rented. Multiple the days by the $30 day charge, and add it to the initial rental charge.

Buddy's Rental Car: f(x) 36 + (28x)

The x represents the number of days the car is rented. Multiple the days by the $28 day charge, and add it to the initial rental charge.

Now, input 10, for the number of days you want to rent the car for!

Andy's Rental Car: f(10)= 20 + (30 x 10)

20 + (300)

f(x) = $320

Buddy's Rental Car: f(10) = 36 + (28 x 10)

36 + (280)

f(x) = $316

So, it would be $4 cheaper to rent from Buddy's Rental Car company than Andy's Rental Car company!

Hope this helps! :)

7 0

3 years ago