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kati45 [8]
3 years ago
6

Complete the sentence. 7 is 1/10 of

Mathematics
2 answers:
Schach [20]3 years ago
5 0
7 is 1/10 of.. 70, because 10 times 7 is 70 :)
Lisa [10]3 years ago
4 0
7 times 10 equals 70.
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Jackie won tickets playing the bowling game at the local arcade. The first time, she won 6 tickets. The second time, she won a b
Alborosie

Answer:

it might be 48 tickets.

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2 years ago
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Margo borrows $1000, agreeing to pay it back with 5% annual interest after 15 months. How much interest will she pay?
GuDViN [60]
The answer is $50. Hope this helps!
4 0
4 years ago
£3.50= %of£10 answer this question i raelly dont get it in any way
ziro4ka [17]
\dfrac{\pounds 3.50}{\pounds10}\cdot100\%=\\
0.35\cdot100\%=\\
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3 0
3 years ago
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.895 g and a standard deviation
kvasek [131]

Answer:

3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 0.895, \sigma = 0.292, n = 37, s = \frac{0.292}{\sqrt{37}} = 0.048

Find the probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

This is the pvalue of Z when X = 0.809.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.809 - 0.895}{0.048}

Z = -1.79

Z = -1.79 has a pvalue of 0.0367

3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

5 0
3 years ago
What is the mean of -71,-62,-88-38-89,15,-76
olga nikolaevna [1]
71
62
88
38
89
76
-15 (i'm inversing everything to make it simple)
The mean is -69.28

6 0
3 years ago
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