Answer:
![\dfrac{14}{29}](https://tex.z-dn.net/?f=%5Cdfrac%7B14%7D%7B29%7D)
Step-by-step explanation:
Let <em>P(A) </em>be the probability that goggle of type A is manufactured
<em>P(B) </em>be the probability that goggle of type B is manufactured
<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.
According to the question,
<em>P(A)</em> = 30%
<em>P(B)</em> = 70%
<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.
P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.
will be the probability that a goggle is of type A and is returned within 10 days of its purchase.
will be the probability that a goggle is of type B and is returned within 10 days of its purchase.
![P(E \cap A) = P(A) \times P(E/A)](https://tex.z-dn.net/?f=P%28E%20%5Ccap%20A%29%20%3D%20P%28A%29%20%5Ctimes%20P%28E%2FA%29)
![P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%](https://tex.z-dn.net/?f=P%28E%20%5Ccap%20A%29%20%3D%20%5Cdfrac%7B30%7D%7B100%7D%20%5Ctimes%20%5Cdfrac%7B5%7D%7B100%7D%5C%5C%5CRightarrow%20P%28E%20%5Ccap%20A%29%20%3D%201.5%20%5C%25)
![P(E \cap B) = P(B) \times P(E/B)](https://tex.z-dn.net/?f=P%28E%20%5Ccap%20B%29%20%3D%20P%28B%29%20%5Ctimes%20P%28E%2FB%29)
![P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%](https://tex.z-dn.net/?f=P%28E%20%5Ccap%20B%29%20%3D%20%5Cdfrac%7B70%7D%7B100%7D%20%5Ctimes%20%5Cdfrac%7B2%7D%7B100%7D%5C%5C%5CRightarrow%20P%28E%20%5Ccap%20B%29%20%3D%201.4%20%5C%25)
![P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%](https://tex.z-dn.net/?f=P%28E%29%20%3D%201.5%20%5C%25%20%2B%201.4%20%5C%25%20%5C%5CP%28E%29%20%3D%202.9%5C%25)
If a goggle is returned within 10 days of its purchase, probability that it was of type B:
![P(B/E) = \dfrac{P(E \cap B)}{P(E)}](https://tex.z-dn.net/?f=P%28B%2FE%29%20%3D%20%5Cdfrac%7BP%28E%20%5Ccap%20B%29%7D%7BP%28E%29%7D)
![\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B1.4%20%5C%25%7D%7B2.9%5C%25%7D%5C%5C%5CRightarrow%20%5Cdfrac%7B14%7D%7B29%7D)
So, the required probability is ![\dfrac{14}{29}.](https://tex.z-dn.net/?f=%5Cdfrac%7B14%7D%7B29%7D.)
Ok so your first step is to make this an equation
she gets paid x amount per hour and she works for 22 hours
so 22x plus her bonus
22x + 500 =1204
so now solve the equation
subtract both sides by 500
22x +500 =1204
-500 = -500
to get
22x = 704
now divide both sides by 22
x = 32
mrs jackson worked 32 hours to get her pay check
Answer:
2X-1
Step-by-step explanation:
as far as i got
Step-by-step explanation:
︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼
Answer18:
The quadrilateral ABCD is not a parallelogram
Answer19:
The quadrilateral ABCD is a parallelogram
Step-by-step explanation:
For question 18:
Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)
The slope of a line is given m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
Now,
The slope of a line AB:
m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
m=![\frac{6-(-1)}{(-4)-(-4)}](https://tex.z-dn.net/?f=%5Cfrac%7B6-%28-1%29%7D%7B%28-4%29-%28-4%29%7D)
m=![\frac{7}{0}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B0%7D)
The slope is 90 degree
The slope of a line BC:
m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
m=![\frac{6-6}{(-4)-(-1)}](https://tex.z-dn.net/?f=%5Cfrac%7B6-6%7D%7B%28-4%29-%28-1%29%7D)
m=![\frac{0}{(-3)}](https://tex.z-dn.net/?f=%5Cfrac%7B0%7D%7B%28-3%29%7D)
The slope is zero degree
The slope of a line CD:
m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
m=![\frac{(-4)-6}{2-2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28-4%29-6%7D%7B2-2%7D)
m=![\frac{-10}{0}](https://tex.z-dn.net/?f=%5Cfrac%7B-10%7D%7B0%7D)
The slope is 90 degree
The slope of a line DA:
m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
m=![\frac{(-1)-(-4)}{(-4)-(2)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28-1%29-%28-4%29%7D%7B%28-4%29-%282%29%7D)
m=![\frac{3}{-6}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B-6%7D)
m=![\frac{-1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D)
The slope of the only line AB and CD are the same.
Thus, The quadrilateral ABCD is not a parallelogram
For question 19:
Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)
The slope of a line is given m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
Now,
The slope of a line AB:
m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
m=![\frac{2-3}{3-(-2)}](https://tex.z-dn.net/?f=%5Cfrac%7B2-3%7D%7B3-%28-2%29%7D)
m=![\frac{-1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B5%7D)
The slope of a line BC:
m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
m=![\frac{(-1)-2}{2-3}](https://tex.z-dn.net/?f=%5Cfrac%7B%28-1%29-2%7D%7B2-3%7D)
m=![\frac{-3}{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B-3%7D%7B-1%7D)
m=3
The slope of a line CD:
m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
m=![\frac{0-(-1)}{(-3)-2}](https://tex.z-dn.net/?f=%5Cfrac%7B0-%28-1%29%7D%7B%28-3%29-2%7D)
m=![\frac{-1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B5%7D)
The slope of a line DA:
m=![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
m=![\frac{3-0}{(-2)-(-3)}](https://tex.z-dn.net/?f=%5Cfrac%7B3-0%7D%7B%28-2%29-%28-3%29%7D)
m=3
The slope of the line AB and CD are the same
The slope of the line BC and DA are the same
Thus, The quadrilateral ABCD is a parallelogram