Answer:
The number of mollies fishes in the aquarium is 20 .
Step-by-step explanation:
Given as :
The capacity of aquarium = 40 gallons
∵ 1 gallon = 4 quart
∴ 40 gallons = 4 × 40 = 160 quart
Now, According to question
0.25 inches of fish required 1 quart capacity
I.e for 1 quart capacity , 0.25 inches fish
So. for 160 quart capacity , 0.25 × 160 = 40 inches fishes
Now the size of mollies fish = 2 inches
Then , number of mollies fish = 
I.e Number of mollies fish = 
= 20
Hence The number of mollies fishes in the aquarium is 20 . Answer
<span>Constraints (in slope-intercept form)
x≥0,
y≥0,
y≤1/3x+3,
y</span>≤ 5 - x
The vertices are the points of intersection between the constraints, or the outer bounds of the area that agrees with the constraints.
We know that x≥0 and y≥0, so there is one vertex at (0,0)
We find the other vertex on the y-axis, plug in 0 for x in the function:
y <span>≤ 1/3x+3
y </span><span>≤1/3(0)+3
y = 3.
There is another vertex at (0,3)
Find where the 2 inequalities intersect by setting them equal to each other
(1/3x+3) = 5-x Simplify Simplify Simplify
x = 3/2
Plugging in 3/2 into y = 5-x: 10/2 - 3/2 = 7/2
y=7/2
There is another vertex at (3/2, 7/2)
There is a final vertex where the line y=5-x crosses the x axis:
0 = 5 -x , x = 5
The final vertex is at point (5, 0)
Therefore, the vertices are:
(0,0), (0,3), (3/2, 7/2), (5, 0)
We want to maximize C = 6x - 4y.
Of all the vertices, we want the one with the largest x and smallest y. We might have to plug in a few to see which gives the greatest C value, but in this case, it's not necessary.
The point (5,0) has the largest x value of all vertices and lowest y value.
Maximum of the function:
C = 6(5) - 4(0)
C = 30</span>
2x=12 is an equation with the solution of 6
