Hi!
An obtuse angle is one greater than 90 degrees, a right angle one that is 90, and acute less than 90.
An obtuse triangle is one with one obtuse angle, all the rest being acute. A right triangle is one with one right angle, all the rest acute. And finally, an acute triangle is one with three acute angles.
In this case, the angles measure 83 degrees, 31 degrees, and 66 degrees. All of them are acute angles, as they're all less than 90 degrees.
Therefore, the triangle is an acute triangle.
Hope this helped!
5.95 is your answer. Have a wonderful day
The term rules for the following sequences is that you multiply each number by 3! Hope this helps and please mark brainliest :)
The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.
<h3>What is green's theorem?</h3>
The theorem states that,

Where C is the curve.
<h3>Calculation:</h3>
The given line integral is

Where curve C is a circle x² + y² = 4;
Applying green's theorem,
P = 9y³; Q = -9x³
Then,



⇒ 
Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as
0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π
Then the integral becomes

⇒ 
⇒ 
⇒ 
⇒ 
⇒ ![-108[2\pi - 0]](https://tex.z-dn.net/?f=-108%5B2%5Cpi%20-%200%5D)
⇒ -216π
Therefore, the required value is -216π.
Learn more about green's theorem here:
brainly.com/question/23265902
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Answer:
Since both terms are perfect squares, factor using the difference of squares formula,
a2−b2=(a+b)(a−b) where a=x and b=16.(+)x16)
Step-by-step explanation: