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4 years ago

11

When Keenan finished the next level of his video game, he lost 20 points for each five targets he missed and won 95 points for f

ast level completion.

1 answer:

Dmitrij [34]4 years ago

4 0

What is the rest of the question

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sam said the absoulute value of 14 is -14. Kai said the absolute value of 14 is 14. Who is correct. Explain

Hoochie [10]

Answer:

Kai is right.

Step-by-step explanation:

Absolute Value is always positive.

4 0

3 years ago

What is the first step in solving this equation? 2(3x - 4) = 3x + 1 a combine like terms b move x to the other side c distributi

laila [671]

You need to do the distributive property first so the answer is C

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3 years ago

A student has 54 coins in a bank. There are only quarters, nickels, and dimes in the bank. If there are twice as many dimes as q

r-ruslan [8.4K]

The student would have 18 dimes in the bank.. 54 coins. x+2x+3x=54
6x=54

18 dimes,
9 quarters
27 nickles.

5 0

3 years ago

Calculate sum5.3 +(-7.45) =

dsp73

Answer: -43/20

Step-by-step explanation: you just need a college calculator to solve ,you need to just plug the numbers and it will do it for you.

6 0

3 years ago

Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3

Whitepunk [10]

If $f(x)=4x-3$ :

$\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4$

If $f(x)=4x^{-3}$ :

$\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}$

$\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}$

$\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}$

7 0

4 years ago