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3 years ago

Solve the math problem please

Mathematics

2 answers:

DedPeter [7]3 years ago

6 0

Answer:

Choice B

Step-by-step explanation:

TRUST ME. IF YOU WANT EXPLANATION:

54 - 10x < = 20 + 7x

54 - 20 < = 7x + 10x

34 < = 17x

34/17 < = x

2 < = x.....or x > = 2....its B trust me

mars1129 [50]3 years ago

5 0

Answer:

B, x≥2

Step-by-step explanation:

54 - 10x ≤ 20 + 7x - subtract 20

34 - 10x ≤ 7x - add 10x to 7x

34 ≤ 17x - divide 34 by 7

2 ≤ x - flip the equation - x ≥ 2

Hope this is helpful!

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Which of the following equations have complex roots?

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Answer:

Step-by-step explanation:

Complex roots of quadratic functions occur when the discriminant is negative.

Discriminant

$b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0$

Evaluate the discriminant of each of the given equations.

$\textsf{A.} \quad 3x^2+2=0$

$\implies a=3, \quad b=0, \quad c=2$

$\implies b^2-4ac=0^2-4(3)(2)=-24$

As -24 < 0 the equation will have complex roots.

$\textsf{B.} \quad 2x^2+1=7x$

$\implies 2x^2-7x+1=0$

$\implies a=2, \quad b=-7, \quad c=1$

$\implies b^2-4ac= (-7)^2-4(2)(1)=41$

As 41 > 0 the equation does not have complex roots.

$\textsf{C.} \quad 3x^2-1=6x$

$\implies 3x^2-6x-1=0$

$\implies a=3, \quad b=-6, \quad c=-1$

$\implies b^2-4ac=(-6)^2-4(3)(-1)=48$

As 48 > 0 the equation does not have complex roots.

$\textsf{D.} \quad 2x^2-1=5x$

$\implies 2x^2-5x-1=0$

$\implies a=2, \quad b=-5, \quad c=-1$

$\implies b^2-4ac=(-5)^2-4(2)(-1)=33$

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

brainly.com/question/27869538

Learn more about complex roots here:

brainly.com/question/26344541

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