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Lubov Fominskaja [6]
4 years ago
6

Write the quadratic function c(x)=x^2+6x+14 in vertex form

Mathematics
1 answer:
sergiy2304 [10]4 years ago
4 0

Answer:

c(x)=(x+3)^2+5

Step-by-step explanation:

c(x)=x^2 + 6x + 14 = x^2+6x+9 + 5 = (x+3)^2+5

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Evaluate each rational expression using given values
Anestetic [448]

To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.

8 0
3 years ago
M 2 = aº, m 3 = bº, m 41<br> a<br> b<br> a + b<br> a-b
Oduvanchick [21]

Answer:

m,4+ a+b

Step-by-step explanation:

an exterior angle equals the sum of the 2 opposite interior angles

7 0
3 years ago
Given that 2x − 1∶ − 4 = 16x + 1 ∶ 2x − 1 find the possible values of
IRISSAK [1]

The possible values of x are 5 and -1/12

<h3>Complete question</h3>

Given that 2x − 1∶ x − 4 = 16x + 1 ∶ 2x − 1 find the possible values of x

<h3>How to determine the possible values of x?</h3>

The ratio is given as:

2x − 1∶ x − 4 = 16x + 1 ∶ 2x − 1

Express as fraction

\frac{2x - 1}{x-4} = \frac{16x + 1}{2x -1}

Cross multiply

4x^2 -4x + 1 = 16x^2 + x  -64x - 4

Collect like terms

-16x^2 + 4x^2 + 64x - x - 4x + 1 + 4 = 0

Evaluate the like terms

-12x^2 + 59x + 5 = 0

Divide through by -1

12x^2 - 59x - 5 = 0

Expand

12x^2  + x - 60x - 5 = 0

Factorize

x(12x + 1) - 5(12x + 1) = 0

Factor out 12x + 1

(x - 5)(12x + 1) = 0

Expand

x  - 5 = 0 or 12x + 1 = 0

Solve for x

x = 5 or x = -1/12

Hence, the possible values of x are 5 and -1/12

Read more about ratios at:

brainly.com/question/2328454

#SPJ1

8 0
2 years ago
Is the origin located at the intersection of the x - and y -axis
Nastasia [14]

yes it is because thats exactly where its located

4 0
3 years ago
Find the first, fourth, and eighth terms of the sequence. A(n) = –3 • 2^n–1
Sphinxa [80]
A(n) = –3 • 2⁽ⁿ⁻¹⁾

for n = 1 ,  A₁ = -3.(2)⁰ = -3
for n = 2 ,  A₂ = -3.(2)¹ = -6
for n = 3 ,  A₃ = -3.(2)² = -12
for n = 4 ,  A₄ = -3.(2)³ = -24
...........................................
for n = 8 ,  A₈ = -3.(2)⁷ = -384


4 0
3 years ago
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