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3 years ago

Select yes or no to state whether each data set is likely to be normally distibuted

Mathematics

1 answer:

Anarel [89]3 years ago

3 0

it is yes, then no, then yes.

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Two cars leave town at the same time and travel in opposite directions. Speed of car A is 12 km/h more than car B. They are 312k

Zina [86]

Answer:

Speed of car B is 33 km/h and speed of car A is $45\,\,km/h$

Step-by-step explanation:

Let speed of car B be $x$ km/h

Speed of car A is 12 km/h more than car B.

Therefore,

Speed of car A = $(12+x)$ km/h

Distance = Speed × Time

Distance travelled by car A in 4 hours = $4(12+x)$ km = $(48+4x)$ km

Distance travelled by car B in 4 hours = $4x$ km

Also, cars A and B are 312km apart after 4 hours.

$48+4x+4x=312\\48+8x=312\\8x=264\\\\x=\frac{264}{8}\\\\x=33\,\,km/h$

Speed of car B is 33 km/h and speed of car A is $12+x=12+33=45\,\,km/h$

5 0

2 years ago

2(x - 4) - 2 = 5x + 23<br> x= ?

crimeas [40]

X=-11 :) let me know if you need more help!

3 0

3 years ago

10 cm equal to cm can you help me.

Olenka [21]

Answer:

1000cm

Step-by-step explanation:

there are 100cm in a meter. so we multiply 10 by 100 to get the amount of centimeters in 10 meters which is 1000cm

4 0

2 years ago

Read 2 more answers

Karen walked three miles in 48 mins. Bob walked one mile further than Karen. If it took Bob 1 hour and 5 min to complete his wal

nlexa [21]

Answer:

Karen

Step-by-step explanation:

Karen because it took bob and extra minute to walk the last mile.

8 0

2 years ago

Read 2 more answers

Simplify (x^2)^3*5x/6x^2*15x^3

nasty-shy [4]

When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2

<h3>Data obtained from the question</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Simplification =?

<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]

Recall

(M^a)^b = M^ab

Thus,

(x^2)^3 = x^6

[(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]

Recall

M^a × M^b = M^(a+b)

Thus,

x^6 × 5x = 5x^(6 + 1) = 5x^7

6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5

[x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5

Recall

M^a ÷ M^b = M^(a - b)

Thus,

5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2

Therefore,

[(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2

Learn more about algebra:

brainly.com/question/2768008

#SPJ1

8 0

1 year ago