Answer:
x =48.6
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp side / hypotenuse
sin x = 54 /72
Taking the inverse sin of each side
sin ^ -1( sin x) =sin ^-1 ( 54/72)
x = 48.59037789
To the nearest tenth
x =48.6
Answer:
y = 4/3x - 7
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.
Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.
In quadrilateral ABCD:
∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)
Substituting:
47 + 39 + 112 + ∠D = 360
∠D + 198 = 360
∠D = 360 - 198
∠D = 162°
The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:
∠A = ∠E = 47°
∠B = ∠F = 39°
∠C = ∠G = 112°
∠D = ∠H = 162°
Answer:
b is 10 degrees and a is 64 degrees.
Step-by-step explanation:
Properties of a parallelogram needed for this problem: Opposite angles are congruent and adjacent angles are supplementary, meaning they add to 180 degrees.
This means that in the picture, 2a and 12b+8 are equal, while 2a and 5b+2 are supplementary.
From this we can make two equations:
2a=12b+8
and
2a+5b+2=180
If we subtract 5b+2 in the second equation, both equations will equal 2a. I'll explain why that's good. We end up with:
2a=12b+8
and
2a=180-5b-2
Now, we can set the two equations equal to each other because they both equal the same thing. Then simplify.
12b+8=180-5b-2
17b=170
b=10
Knowing b is 10 degrees, we can easily plug that back into one of our original two equations. I'll choose 2a=12b+8.
2a=12(10)+8
2a=120+8
2a=128
a=64
b is 10 degrees and a is 64 degrees.
Answer:
10in by 5in
Step-by-step explanation:
PERIMETER: p=2(a+b) p=30
AREA: A=a×b A=50
2(a+b)=30
a×b=50
