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Gre4nikov [31]
4 years ago
15

Solve by square rooting : 3(X+2)^2:8​

Mathematics
1 answer:
dolphi86 [110]4 years ago
3 0

The value of x is √8/3 - 2

Step by step explanation:

The given equation is

3(x+2)^2=8

To find x,

(x+2)²= 8/3

By taking square root on both sides

x+2= √8/3

x=√8/3 -2

x= -0.37

Thus the square root for the given value is -0.37

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If I had 200 juul pods and 400 juuls how many more pods do I have to buy in order for every juul to have a pod?
Lena [83]

Answer:

You have to buy 200 more juul pods.

Step-by-step explanation;

400-200 = The amount of juul pods needed for every juul to have a pod.

400-200 = 200

6 0
3 years ago
Read 2 more answers
100 PTS!! Will give Brainliest...
nydimaria [60]

Answer:

shifted left 7 & shifted down 3

Step-by-step explanation:

8 0
3 years ago
How many eighths are there in 4 3/8<br>ANSWER:​
VashaNatasha [74]

Answer:

35/8

Step-by-step explanation:

4×8= 32 plus the 3/8 equals 35/8

hope it helps

7 0
3 years ago
(h+k)(2)=?<br> (h-k)(3)=?<br> 3h(2)+2k(3)=?
marusya05 [52]

Answer:

see explanation

Step-by-step explanation:

(h + k)(x) = h(x) + k(x), thus

h(x) + k(x)

= x² + 1 + x - 2 = x² + x - 1 , then

(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5

----------------------------------------------------

(h - k)(x) = h(x) - k(x), thus

h(x) - k(x)

= x² + 1 - (x - 2) = x² + 1 - x + 2 = x² - x + 3, then

(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9

-----------------------------------------------------

h(2) = 2² + 1 = 4 + 1 = 5

k(3) = 3 - 2 = 1

Thus

3h(2) + 2k(3)

= 3(5) + 2(1) = 15 + 2 = 17

8 0
3 years ago
PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0
2 years ago
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