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2 years ago

1. What is the volume of the prism that can be constructed from this net?

Mathematics

1 answer:

Irina-Kira [14]2 years ago

3 0

1. V = lwh
V = (8)(4)(5)
V = (32)(5)
V = 160 units³

2. V = lwh + lwh
V = (4)(2)(1) + (3)(1)(1)
V = (8)(1) + (3)(1)
V = 8 + 3
V = 11 units³

3. V = leh + s³
V = (9)(3)(4) + (3)³
V = (27)(4) + 27
V = 108 + 27
V = 135 units³

4. V = lwh
V = (3)(7)(2)
V = (21)(2)
V = 42 units³

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Step by step explanation thanks

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Answer:

C= 7y +150

850

250

Step-by-step explanation:

The cost is 7 times y, the number of yearbooks, plus 150, the upfront cost.

7 times 100 is 700, plus 150 is 850.

1900-150 is 1750 divided by 7 is 250

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2 years ago

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If it requires 6 pounds of wild caught animals to create 1 pound of salmon, what percent of the wild caught animals are wasted?

Oduvanchick [21]

The percentage of animal wasted is the number of animal wasted over 100

85.7% of the wild caught animals are wasted

<h3>How to calculate the animal wasted</h3>

From the question, we have:

Animals caught = 6 pounds

Salmon = 1 pound

The total weight in the system is:

Total = 6 pounds + 1 pound

So, we have:

Total = 7 pounds

The percent of wild caught animals wasted is then calculated as:

$\%Wasted = \frac{6}{7} * 100\%$

Simplify

$\%Wasted = 85.7\%$

Hence, 85.7% of the wild caught animals are wasted

Read more about percentage at:

brainly.com/question/843074

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1 year ago

39 less than twice a number is 5 times the sum of a number and two times the number. Find the number

umka2103 [35]

$2n - 39 = 5(n + 2n)\\2n - 39 = 5(3n)\\2n - 39 = 15n\\2n = 15n + 39\\-13n = 39\\\\n = -3$

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3 years ago

The ratio of the volume of soda in glass A to the volume of glass B is 8/3 to 7/2

MrRa [10]

Answer:

Total volume in the two glasses is 740 mL.

Step-by-step explanation:

Given:

Ratio of the volume of soda in glass A to the volume of glass B = 8/3 : 7/2

Volume of soda in glass A = 320mL

To Find :

The total volume in the two glasses = ?

Solution:

Let the volume of soda in glass B be x

then

$\text{ratio of soda in glass A} \times \text{ the volume of soda in glass B} = \text{ratio of soda in glass B} \times \text{ the volume of soda in glass A}$