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Burka [1]
4 years ago
15

Simplify the square root of 27x^12/300x^8

Mathematics
2 answers:
Darina [25.2K]4 years ago
6 0
The first thing we are going to do is rewrite the expression correctly.
 We have:
 root (27x ^ 12 / 300x ^ 8)
 Rewriting:
 root ((27/300) * (x ^ 12 / x ^ 8))
 root ((9/100) * (x ^ (12-8)))
 root ((9/100) * (x ^ (4)))
 root ((9/100) * (x ^ (4)))
 3 * x ^ 2 * root ((1/100)
 (3 * x ^ 2) / 10
 (3/10) * (x ^ 2)
 Answer:
 (3/10) * (x ^ 2)
antoniya [11.8K]4 years ago
4 0

Answer:

3/10 x^2

Step-by-step explanation:

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When -3v = -18 is solved, the result is:
rjkz [21]

Answer:

When -3v = -18 is solved, the result is:

21v

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2 years ago
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What is 1/2 times 1/2 times 3/4
kompoz [17]

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0.1875 = 1875/10000 = 3/16

Step-by-step explanation:

First its 0.1875 but if u need to make it into a fraction its 3/16

Hope this helps  :)

8 0
3 years ago
40 POINTS AND BRAINLIEST<br><br> Which function rule describes the pattern in the table?
worty [1.4K]

Answer:

y= -x-2

Step-by-step explanation:

y=ax+b

x= -2; y=0 => 0=-2a+b; b=2a

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2a=a-1=> a= -1; b= -2

=> y= -x-2

3 0
3 years ago
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The point P(x, y) lies on the terminal side of an angle = –60° in standard position. What are the signs of the values of x and y
pantera1 [17]

Answer:

  x is positive, and y is negative

Step-by-step explanation:

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8 0
3 years ago
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Please help this question.
sergejj [24]

Answer:

a). 59.049°C

b). 2.1179 seconds

Step-by-step explanation:

Expression representing the final temperature after decrease in temperature of the metal from 100°C to T°C is,

T = 100(0.9)^{x}

where x = duration of cooling

a). Temperature when x = 5 seconds

T = 100(0.9)⁵

  = 59.049

  ≈ 59.049°C

b). If the temperature of the metal decreases from 100°C to 80°C

Which means for T = 80°C we have to calculate the duration of cooling 'x' seconds

80 = 100(0.9)^{x}

0.8 = (0.9)^{x}

By taking log on both the sides

log(0.8) =log[(0.9)^{x}]

-0.09691 = x[log(0.9)]

-0.09691 = -0.045757x

x = \frac{0.09691}{0.045757}

x = 2.1179

x ≈ 2.1179 seconds

3 0
3 years ago
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