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3 years ago

What goes into 49 and 50 evenly

Mathematics

2 answers:

solniwko [45]3 years ago

8 0

Nothing, goes into 49 and 50.

Margaret [11]3 years ago

5 0

7x7=49 and 5x10=50 to let you know

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Which expression is equivalent to 9 p minus 3 p + 2? 8p 14p 6 p + 2 9 p minus 1

tankabanditka [31]

Your answer is c.

Step-by-step explanation: Let’s say P is worth 1: 9 times 1 equals 9: 3 times 1 equals 3: 9 - 3 = 6/ 6 + 2 equals 8. Now this is C: 6 times 1 equals 6/ 6+ 2 = 8

7 0

3 years ago

Read 2 more answers

What is the units digit of 2 to the 50th power

11111nata11111 [884]

Notice that

$2^1=2$
$2^2=4$
$2^3=8$
$2^4=16$
$2^5=32$

so that for each power of 2, there is a pattern of period 4. This means that for integers $k\ge0$ , each of $2^{4k}$ , $2^{4k+1}$ , $2^{4k+2}$ , and $2^{4k+3}$ have the same units digit.

We can write $50=4(12)+2$ , and since $3=4(0)+2$ , it follows that $2^{50}$ and $2^3$ share the same units digits. So the units digit of $2^{54}$ is 8.

6 0

3 years ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

Answer-

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

Solution-

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$