<span>Answer:
MgF2 ====⇒ Mg+2 + 2F-
Ksp = [Mg+2][F-]^2
Let S = molar solubility of MgF2
[Mg+2] = S ; [F-] = 2s
Since the [F-] is initially 0.40 M, then [F-] = 0.40 + 2S
6.4 x 10^-9 = (S) (0.40 + 2S)^2 ; one can neglect the 2S in the 0.40 + 2S expression since it is very, very small compared to the 0.40 already present.
6.4 x 10^-9 = S(0.40)^2
S = 4.0 x 10^-8
Molar solubility = 4.0 x 10^-8</span>
Answer:
1. sum of term = 465
2. nth term of the AP = 30n - 10
Step-by-step explanation:
1. The sum of all natural number from 1 to 30 can be computed as follows. The first term a = 1 and the common difference d = 1 . Therefore
sum of term = n/2(a + l)
where
a = 1
l = last term = 30
n = number of term
sum of term = 30/2(1 + 30)
sum of term = 15(31)
sum of term = 465
2.The nth term of the sequence can be gotten below. The sequence is 20, 50, 80 ......
The first term which is a is equals to 20. The common difference is 50 - 20 or 80 - 50 = 30. Therefore;
a = 20
d = 30
nth term of an AP = a + (n - 1)d
nth term of an AP = 20 + (n - 1)30
nth term of an AP = 20 + 30n - 30
nth term of the AP = 30n - 10
The nth term formula can be used to find the next term progressively. where n = number of term
The sequence will be 20, 50, 80, 110, 140, 170, 200..............
Answer:
x=7.4
Step-by-step explanation:
2.4+x=9.8
(x=9.8-2.4)
x=7.4
Complete Question
Sophie pays m dollars to rent a car for the weekend. On the drive home, she buys $45 worth of gasoline. Her friend Melody pays for one-half the cost of the car rental only. Write an expression you could use to determine how much Sophie spent.
Answer:
1/2m + 45
Step-by-step explanation:
We are told in the question that:
On the drive home, she buys $45 worth of gasoline.
Her friend Melody pays for one-half the cost of the car rental only.
Sophie pays m dollars to rent a car for the weekend.
The amount sophie pays for car rental = m - 1/2m
= 1/2m
Therefore, the expression used to determine how much sophie spent is written as:
1/2 × $m + $45
1/2m + 45
Answer:
AB
Step-by-step explanation:
the hypotenuse is always the longest side in a triangle
