Answer:
Step-by-step explanation:
<u>Given data:</u>
Base = b = 4 cm
Height = h = 4 cm
<u>Required:</u>
Area of triangle = A = ?
<u>Formula:</u>
A = bh / 2
<u>Solution:</u>
A = (4)(4) / 2
A = 16 / 2
A = 8 cm²
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45
Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239
Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102
Solving for y,
y = -2(102) + 239
y = 35
Solving for z,
z = 102 - 45
z = 57
<u>Number + 5 = 10</u>
Subtract 5 from each side:<em> Number = 5</em>
Answer: uh I think its a carrot, sorry i hope this could maybe help :)
Step-by-step explanation:
