All categories

3 years ago

The length of a rectangle is 5 less thsn twice it's width. The perimeter is 26 meters. Find the deminsion of rectangle

Mathematics

1 answer:

Reptile [31]3 years ago

3 0

Answer:Width is 6 meters and length is 7 meters

Step-by-step explanation:Let width be

and length be

. We know that the length of the rectangle is 5 less than twice its width. This can be written as:

−

We also know that the perimeter of the rectangle is 26 meters. The perimeter is the sum of all sides: 2 widths + 2 lengths.

(

)

We now have two equations which we can solve simultaneously. Substitute

−

into the second equation:

(

−

)

Now that we have a value for

(width), we can sub this value into the first equation to get

(length).

(

)

−

There are other methods you can use to solve simultaneous equations.

Hope this helps :)

You might be interested in

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago

Question attached. Please advise.

shusha [124]

Confusing to me, sorry i cant help. I am not good with graphs.

4 0

3 years ago

If △ABC ~ △DEF which of the following statements are correct?

DanielleElmas [232]

The correct answer to this question is the last choice (angle B is equal to angle E). When given a question like this, always remember that corresponding angles of congruent triangles are congruent. In simpler terms, the letters that are in the same position in two different congruent triangles are congruent. Therefore, since B is the second letter in ABC and E is the second letter in DEF, we know the last choice is correct.

I hope this helps.

5 0

3 years ago

Rita gets paid $16 per hour for the first 8 hour she works each day. she earns 1 1/2 her hourly pay rate for times she works ove

Andrej [43]

8:15 a.m to 12:45 p.m......4 hrs 30 min
took 45 min lunch (not paid)....now its 1:30 p.m.....
1:30 p.m. to 6:45 pm = 5 hrs 15 min

5 hrs 15 min + 4 hrs 30 min = 9 hrs 45 min or 9 3/4 hrs

$ 16 for first 8 hrs......overtime pay is $ 24 per hr....leaving 1 hr and 45 min or 1 3/4 hrs overtime
16 + 24(7/4) = 16 + 42 = $ 58 <===

3 0

3 years ago

Some equations have the form y=kxy=kx, where kk is a number.

miv72 [106K]

Answer:

$x = 4y$