Compute the gradient of 
.
Set this equal to the zero vector and solve for the critical points.
The last case has no real solution, so we can ignore it.
Now,
so we have two critical points (0, 0) and (2, 2).
Compute the Hessian matrix (i.e. Jacobian of the gradient).
Check the sign of the determinant of the Hessian at each of the critical points.
which indicates a saddle point at (0, 0);
We also have 
, which together indicate a local minimum at (2, 2).
Answer:
The 2017 year is out of proportion.
Step-by-step explanation:
That graph should be at about half to 3/4 the height of the average heights of the other bars.
Answer:
Step-by-step explanation:
9
The answer is 41.25
hope this helps
The first step to solve this problem is to represent
variables for the width and the length:
Let w = width of the rectangle
2w – 1 = length
of the rectangle
The formula to compute for the area of the rectangle is:
A = LW
Substituting the values and variables to the formula:
28 = w (2w – 1)
2w^2 – w = 28
2w^2 – w – 28 = 0
Solve the quadratic equation:
(2w + 7)(w – 4) = 0
w = -7/2 or w = 4
You cannot use the -7/2 because there is no negative
measurement.
W = 4 feet
L = 2(4) – 1 = 7 feet
Therefore the dimension of the rectangle is 4 feet by 7
feet.
