(6x + 6) + ( -3

Leokris [45]

416.25

375*.11=41.25

41.25+375=416.25

5 0

3 years ago

(a) Derive an equation of the line passing through the points A(0, 545) and B(4, 726). (Let t be the independent variable and y

a_sh-v [17]

Answer:

The equation of the line is $y=45.25t+545$

Step-by-step explanation:

The general for of a line is:

$y=mt+n$ (1)

where:

$m$ is the slope of the line and $m$ is the intercept with the axis of the dependent variable, $y$ in this case.

In order to obtain the value of the slope ( $m$ ) we can use the corresponding slope formula:

$m=\frac{y_{2}-y_1 }{t_2-t_1}$ (2)

where $t_1, t_2, y_1$ and $y_2$ are the corresponding coordinates of the given points. In this case:

$t_1=0\\t_2=4\\y_1=545\\y_2=726\\$

Substituting these values in equation (2) we obtain:

$m=\frac{726-545}{4-0}=\frac{181}{4}=45.25\\m=45.25$

Hence, the line equation is now:

$y=45.25t+n$ (3)

Now to obtain the value of $n$ you can follow two options:

You can substitute one of your points, $A$ or $B$ , in equation (3). In this way, you will obtain an equation where the variable is $n$

Note that for this question, it is easier to select point A because of having the independent variable equals to zero $t=0$ . Hence, substituting point A in equation (3):

$45.25*0+n=545\\n=545$

Therefore, the line equation is: $y=45.25t+545$

The second option to find $n$ is to think of the meaning of the <em>intercept</em>. The <em>intercept </em>of a line is defined as the point in which the line crosses the axis of the dependent variable, which also means that the value of the independent variable for this point is zero. From this, we could have automatically said that $n$ is equal to $545$ .

See the attachment for a plot of the line.

7 0

3 years ago

The two sides of a right triangle that are not the hypotenuse are called

IceJOKER [234]

I believe they are called the "Legs." They are also referred to as the opposite and adjacent sides. :)

8 0

3 years ago

What is the value of c so that -12 and 12 are both solutions of x^2-c=108?

murzikaleks [220]

Answer:

c=36

Step-by-step explanation:

Because $x^2-c=108$ can be rewritten as $x^2-c-108=0$ , finding the value of c so that x=(+-)12 solves this equation it means to find the value of c so that $(+-)12^2-c-108=0$ .
Because $12^2=(-12)^2=144$ , we must find c so that $144-c-108=0$ .
Because $144-108=36$ , c=36.
To check, replace c=36 in the initial equation, and check it is a solution for x=(+-)12.