Squirrels forget where they hide about half of their nuts

30. Every week, the number of crickets hiding under Dave's fridge grows by 20%. If there are 60 crickets down there this week, a

Alenkinab [10]

The answer will be d because the crickets will increase in demand

4 0

3 years ago

Whiskers the cat weighs 2 2/3 kg. Piglo weighs 4kg. For each question , write a myipulcation and a division equation, decide whe

Liula [17]

Answer:

1) x= 3/2= 1 1/2

2) x= 2/3

Step-by-step explanation:

1)How many times as heavy as Whiskers is Piglio?

a) Write a multiplication equation for the question.

2 2/3 kg * [x]= 4kg

b) Write a division equation for the question.

4/ 2 (2/3) = x

c) Is the answer greater than 1 or less than 1?

Ans) Greater than 1

d) Find the answer

4/ 8/3= x

x= 3/2= 1 1/2

Pigilo is 1 1/2 times as heavy as whiskers

2)How many times as heavy as Piglio is Whiskers?

a) Write a multiplication equation for the question.

4 kg * [x]= 2 2/3 kg

b) Write a division equation for the question.

2 (2/3)/4 = x

c) Is the answer greater than 1 or less than 1?

Ans) Less than 1

d) Find the answer

8/3/4= x

8/3 * 1/4= x

2/3= x

Whiskers is 2/3 times as heavy as Pigilo.

5 0

3 years ago

Sup people can you help me here.

Sedaia [141]

The answer would be -6

3 0

3 years ago

Tonya has a rectangular rug with an area of 21 square feet. The rug is 4 feet longer than it is wide. Create an equation that ca

marissa [1.9K]

a) The equations to determine the length and the width of the rug are

l = 4 + w and l × w = 21

b) The enlarged rug's area = 60 square feet

Step-by-step explanation:

Step 1 :

Let l be the length and w represent the width of the rectangular rug

Given the area = 21 square feet.

So l × w = 21

Also given, the length is 4 feet longer than the width .

So we have

l = 4 + w

Step 2 :

Using the above 2 equations we have

(4+w)w = 21

w² + 4 w - 21 = 0

(w+7)(w-3) = 0

=> w = -7 or w = 3

Since w is the width of the rug, we take the positive value w = 3 as the width

So w = 3 feet

So

l = 4 + w = 4 +3 = 7 feet

Step 3 :

When a 1.5 foot border is added all the way round the rug, the length and width are increased by 3 feet (1.5 feet on both sides) the rug's enlarged length and the rug's enlarged width is

l = 7 + 3 = 10

w = 3 + 3 = 6

The enlarged rug's area = 10 × 6 = 60 square feet

Step 4 :

Answer :

The equations to determine the length and the width of the rug are

l = 4 + w and l × w = 21

The enlarged rug's area = 60 square feet

7 0

4 years ago

The vertices of ghk above have coordinates g(-3,4), h (1.-3), and k(2,7). the equation of the altitude to hk is

dalvyx [7]

We know that
the equation of the altitude to hk passes through point g and is perpendicular to segment hk

step 1
find the slope segment hk
h (1.-3) k(2,7)
slope m=(y2-y1)/(x2-x1)----> m=(7+3)/(2-1)----> m=10

if two lines are perpendicular
so
m1*m2=-1

the altitude to hk has a slope
m2=-1/10

step 2
with m=-1/10 and point g(-3,4) find the equation of the line
y-y1=m*(x-x1)-----> y-4=(-1/10)*(x+3)---> multiply by 10
10y-40=-x-3----> 10y+x=37-----> equation of the altitude

the answer is
10y+x=37

see the attached figure

8 0

4 years ago