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3 years ago

A bag contains 6 red and 10 black

2 answers:

6 0

Is there anymore information? Or perhaps any answer choices?
If so please put them in the comment section so that I am able to help you :-)

lianna [129]3 years ago

4 0

Umm.. Do you anymore information about this question? if so reply to me ill try to help you :))

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Y = 9(x – 8)2 + 17<br> Standard form

Yakvenalex [24]

Answer:

I think that the answer would be y=18x−127

3 0

4 years ago

Can I get some help on this math problem

pogonyaev

Answer:

$x=3\sqrt{5}$

Step-by-step explanation:

<u>Right Triangles</u>

Right triangles have one of its interior angles with a measure of 90°.

In right triangles the Pythagora's Theorem is satisfied.

Being c the longest side (hypotenuse), a and b the shorter sides (the legs), then:

$c^2=a^2+b^2$

We have modified the image to include some known data. Both triangles are congruent since they share one side, have a right angle, and have the same base length.

This means the value of x can be calculated as the hypotenuse of the triangle 3-6-x:

$x^2=3^2+6^2=9+36=45$

$x=\sqrt{45}=\sqrt{9*5}$

$\boxed{x=3\sqrt{5}}$

4 0

3 years ago

Please answer this ASAP

stellarik [79]

9514 1404 393

Explanation:

1. ∠BAC ≅ ∠BCA, BD ≅ BE, ∆BDA and ∆BEC are right triangles . . . . given

2. ∆ABC is isosceles . . . . definition of isosceles triangle

3. BA ≅ BC . . . . definition of isosceles triangle

4. ∆BDA ≅ ∆BEC . . . . HL theorem

5. AC ≅ CE . . . . CPCTC

4 0

3 years ago

Some rectangles have an area of 36 cm². Let the variable W represent the width of these rectangles. Which expression represents

ZanzabumX [31]

Answer:

The perimeter of the rectangle is expressed as; $P = \frac{72 \ + \ 2W^2}{W}$

Step-by-step explanation:

Given;

area of the rectangle, A = 36 cm²

width of the rectangle, = W

Let L represent the length of the rectangle,

A = L x W

$L = \frac{A}{W} = \frac{36}{W}$

The perimeter of the rectangle is calculated as;

P = 2(L + W)

Substitute the value of L into the above equation;

$P = 2(L + W)\\\\P = 2 (\frac{36}{W} + W)\\\\P = 2 (\frac{36 + W^2}{W} )\\\\P = \frac{72 \ + \ 2W^2}{W}$

Thus, the perimeter of the rectangle is expressed as $P = \frac{72 \ + \ 2W^2}{W}$

8 0

3 years ago

Figure A is the preimage. Which figure is the image of figure A after a dilation with a scale factor of 2 and a center of (0, 0)

Travka [436]

Answer:

Step-by-step explanation:

it is u

4 0

3 years ago

Read 2 more answers