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Katyanochek1 [597]
3 years ago
11

PLEASE HELP MEHHHHHHHH

Mathematics
1 answer:
morpeh [17]3 years ago
4 0
X    |   y
-2   | 49
0    | 1
2    |   \frac{1}{49}
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Let f(x)=cos(x)x^-2<br> F’(x)=
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f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}

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2 years ago
Every one reading this please help! I don't understand this and I will give brainliest to the person that helps first with a goo
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Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.

The length of the poster in its frame is ...
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Likewise, the width of the poster in its frame is ...
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The area of a rectangle 36 in by 28 in is the product of these dimensions:
  Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
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