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2 years ago

Find the missing side Please help thank you!!

Mathematics

2 answers:

Savatey [412]2 years ago

8 0

Answer:

$c= \sqrt{41}$

Step-by-step explanation:

$a^{2} +b^{2} =c^{2} \\4^{2} + 5^{2} = 16 + 25 = \sqrt{41} = c$

ElenaW [278]2 years ago

5 0

Answer:

6.4

Step-by-step explanation:

As we can see it is a right angled triangle so

perpendicular (p)= 5

base (b) = 4

hypotenuse (h) = c = ?

we know

by using Pythagoras theorem,

h² = p² + b²

or h = √(p² + b²)

c = √( 5² + 4 ² )

c = √41

c = 6.4

hope it helps :)

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Pepsi [2]

Hey there!

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50 = 2P divide both sides by 2

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2 years ago

On a coordinate plane, triangle J K L has points (negative 2, 1), (0, 3), and (2, negative 1). Reflect the figure over the line

svetlana [45]

Answer:

J'(2, 1)

K'(0, 3)

Step-by-step explanation:

On a coordinate plane, coordinates of the points J, K and L are (-2, 1), (0, 3) and (2, -1) respectively.

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(x, y) → (-x, y)

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Following this rule coordinates of the images of J' and K' will be

J(-2, 1) → J'(2, 1)

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6 0

2 years ago

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What number gives a result of −8 when 11 is subtracted from the quotient of the number and 6?

natima [27]

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3 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

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It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

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2 years ago

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RUDIKE [14]

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3 years ago

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