Question

What is the surface area of the rectangular pyramid below?

Answer 1

The answer is b. 593.8 ft^2
Solve for the height then plug everything in (attachment shows the formula)

Answer 2

Answer:

The correct option is B.

Step-by-step explanation:

The area of pyramid is the sum of area of rectangular base and 4 triangular sides. Two triangle have base 18 ft and height 14.1 ft. Other two have base 10 ft and height 16 ft.

The area of rectangle is

$A=length\times width$

Length of the base is 18ft and width is 10ft.

$A_1=18\times 10=180$

The area of a triangle is

$A=\frac{1}{2}\times base \times height$

The area of triangle with base 18 ft and height 14.1 ft is

$A_2=\frac{1}{2}\times 18 \times 14.1=126.9$

The area of triangle with base 10 ft and height 16 ft is

$A_3=\frac{1}{2}\times 10 \times 16=80$

The total surface area of the rectangular pyramid is

$A=A_1+2\times A_2+2\times A_3$

$A=180+2\times (126.9)+2\times (80)$

$A=593.8$

The surface area of the rectangular pyramid is 593.8 ft². Therefore the correct option is B.