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3 years ago

Write the equation for g(x)

Mathematics

1 answer:

Rus_ich [418]3 years ago

4 0

Answer:

g(x) = (x+5)²

that's the answer

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Please help me! simplify. 5-[-(-20] a. -3 b.3 c.-7 d.7

frosja888 [35]

Im sorry i dont know

8 0

3 years ago

Zamir needs to determine the height of the building

Svetach [21]

Answer:

Height of the building = 115.4 ft.

Step-by-step explanation:

Height of building = AB + 46.4 + CD + 30.5

By applying Pythagoras theorem in ΔABP,

(26)² = (10)²+ (AB)²

676 - 100 = AB²

AB² = 576

AB = 24 ft

By applying sine rule in ΔCDE,

cos(60°) = $\frac{CD}{CE}$

CD = CE × $\frac{1}{2}$

CD = $\frac{29}{2}$

CD = 14.5 ft

Total Height = 24 + 46.4 + 14.5 + 30.5

= 115.4 ft

6 0

3 years ago

P(x)=×^4-x^2-3 use the remainder theorem and synthetic division to find p(-2)

xxTIMURxx [149]

Answer: p(-2)=9

Step-by-step explanation:

8 0

3 years ago

Solve for x to the nearest 10th. 410 = 1080(0.915)^x

Hunter-Best [27]

Answer:

410/1080=(0.915)^x

0.379=(0.915)^x

ln0. 379/ln0.915=x

X=10.903

4 0

3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago