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3 years ago

What occurs when a muscle becomes weaker and smaller from not being used?

2 answers:

7 0

The best and most correct answer among the choices provided by your question is the third choice.

Atrophy occurs when a muscle becomes weaker and smaller from not being used

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Elenna [48]3 years ago

7 0

<h2>the answer is weight gain hope this helps</h2>

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What does research say about the relationship between birth order, sibling spacing, and intelligence?

vesna_86 [32]

Answer:

"Birth order and sibling spacing are unrelated to a child's intelligence."

Explanation:

The theory, put forward by Robert Zajonc, a psychologist at the University of Michigan, holds, in brief, that the greater the number of children in a family and the shorter the time between their births, the lower will be the intelligence of the children, particularly those born later. A mother's genetics determines how clever her children are, according to researchers, and the father makes no difference. Women are more likely to transmit intelligence genes to their children because they are carried on the X chromosome and women have two of these, while men only have one.

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3 years ago

4 Which of the following is NOT an element of a contract?

MakcuM [25]

D? Seems the most reasonable and the rest seem to be realistic.

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2 years ago

Many long-distance swimmers "carb-load" before an endurance event like a 5 km swim. Carbohydrate loading involves eating carbohy

kati45 [8]

Answer:

Excess glucose is stored as muscle glycogen, reducing the amount of lactate generated in muscle during the event.

Explanation:

Carbohydrates are a main source of energy for the body and loading up on carbohydrates is believed to help store large amountsof energy and is used to help replenish and load muscle glycogen content. Athletes tend to load a few days prior to a long endurance athletic event to help provide adequate and extra energy to muscles.

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4 years ago

PLZ ANSWER ASAP 20 POINTS Ocean currents can be found both on the _____ and_____. Surface currents are driven mainly by ________

butalik [34]

Ocean currents can be found both on the ocean surface and in deep water below 300 meters (984 feet). Surface currents are driven mainly by wind, but sometimes they can be driven by other things such as the movement of animals ect. While the Deep current are while the deep ocean currents are driven by density and temperature gradients. Thermohaline circulation is also known as the ocean's conveyor belt (which refers to deep ocean density-driven ocean basin currents). These currents, called submarine rivers, flow under the surface of the ocean and are hidden from immediate detection.

Sorry wasn't able to answer the last two blanks

Please help me to answer my question too and I might spend more time working on your.

But my Answer Are mostly accurate

6 0

3 years ago

Select ALL the correct answers.

tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$

$10th\ run = 9$

So:

$B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

Required

Select all true statements

(a) & (d) Median Comparisons

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$ $B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

$n = 9$ $n = 10$

Arrange the data:

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$Median = \frac{n + 1}{2}th$

$Median = \frac{9 + 1}{2}th$ $Median = \frac{10 + 1}{2}th$

$Median = \frac{10}{2}th$ $Median = \frac{11}{2}th$

$Median = 5th$ $Median = 5.5}th$ --- average of 5th and 6th

$Median = 2$ $Median = \frac{2+2}{2} = 2$

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$n = 9$ $n = 10$

First, calculate the lower quartile (Q1)

$Q_1 = \frac{n + 1}{4}th$ [Odd n] $Q_1 = \frac{n}{4}th$ [Even n]

$Q_1 = \frac{9 + 1}{4}th$ $Q_1 = \frac{10}{4}th$

$Q_1 = \frac{10}{4}th$ $Q_1 = 2.5$

$Q_1 = 2.5th$

This means that:

$Q_1 = 2nd + 0.5(3rd - 2nd)$ $Q_1 = 2nd + 0.5(3rd - 2nd)$

$Q_1 = 1 + 0.5(1- 1)$ $Q_1 = 1+ 0.5(1 - 1)$

$Q_1 = 1$ $Q_1 = 1$

Next, calculate the upper quartile (Q3)

$Q_3 = \frac{3}{4}(n + 1)th$ [Odd n] $Q_3 = \frac{3}{4}(n)th$ [Even n]

$Q_3 = \frac{3}{4}(9 + 1)th$ $Q_3 = \frac{30}{4}th$

$Q_3 = \frac{30}{4}th$ $Q_3 = 7.5th$

$Q_3 = 7.5th$

This means that:

$Q_3 = 7th + 0.5(8th- 7th)$ $Q_3 = 7th + 0.5(8th- 7th)$

$Q_3 = 2 + 0.5(3- 2)$ $Q_3 = 2+ 0.5(4 - 2)$

$Q_3 = 2.5$ $Q_3 = 3$

The interquartile range is $IQR = Q_3 - Q_1$

So, we have:

$IQR = 2.5 - 1$ $IQR = 3 - 1$

$IQR = 1.5$ $IQR =2$

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0

3 years ago