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Ilya [14]
3 years ago
8

Line a is parallel to line b. Which statement about lines a and b is true?

Mathematics
2 answers:
GalinKa [24]3 years ago
8 0

They both have the same slope.

ivann1987 [24]3 years ago
4 0
They both have the same slope
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Which figure can be formed from the net?
Radda [10]
I dont know if its 100% correct but I believe its this one

5 0
2 years ago
Please help mee pleaseee
nalin [4]

Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

x^3 = 5^5 Raise both sides to the 5th power

x^3 = 3125

x = \sqrt[3]{3125} Apply cube root to both sides

x = \sqrt[3]{125*25}

x = \sqrt[3]{125}*\sqrt[3]{25}

x = \sqrt[3]{5^3}*\sqrt[3]{25}

x = 5*\sqrt[3]{25}

x \approx 14.62009

4 0
3 years ago
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Why is subtracting an expression similar to distributing a –1?
Gre4nikov [31]

Answer: i think D

Step-by-step explanation:

8 0
3 years ago
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I need help so much please help the attachment below is the question i need help on
leonid [27]

Answer:

\dfrac{\sqrt[12]{55296}}{2}

Step-by-step explanation:

Rationalize the denominator, then use a common root for the numerator.

\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\\\\=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\cdot\dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}=\dfrac{2^{\frac{1}{4}+\frac{2}{3}}3^{\frac{1}{4}}}{2}\\\\=\dfrac{2^{\frac{11}{12}}3^{\frac{3}{12}}}{2}=\dfrac{\sqrt[12]{2^{11}3^{3}}}{2}\\\\=\dfrac{\sqrt[12]{55296}}{2}

3 0
3 years ago
Can some help with this question
marissa [1.9K]

Answer:

y + 1 = 3(x - 1)

Step-by-step explanation:

The given point is (1,-1) meaning that x1 = 1 and y1 = -1

The slope of this line is m = 3 because we go up 3 and over to the right 1 (eg: go from the point (1,-1) to (2,2) to see this in action)

Plug these three pieces of info into the point slope formula below

y - y1 = m(x - x1)

y - (-1) = 3(x - 1)

y + 1 = 3(x - 1)

6 0
3 years ago
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