Answer:
you might have to use an app that scans that specific problem :)
Step-by-step explanation:
Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.


We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

According to Pythagoras


.... (1)
Put z=1 and y=2, to find the value of x.




Taking square root both sides.

Differentiate equation (1) with respect to t.

Divide both sides by 2.

Put
, y=2,
in the above equation.

Divide both sides by 2.



Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Answer:
Step-by-step explanation:
x^2 = 64
√x² = √64
x = 8, -8
answer is B
Answer:
x = 7.5
Step-by-step explanation:
Given that BE is parallel to CD and intersects the 2 other sides, then it divides the 2 sides in proportion, that is
=
, substitute values
=
( cross- multiply )
8x = 60 ( divide both sides by 8 )
x = 7.5